1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enyata [817]
3 years ago
7

Find the area of the following shape, given its curves are made from parts of circles with diameters indicated on the diagram. G

ive your answers in terms of π .

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:  Area = 26π + 20 cm²

<u>Step-by-step explanation:</u>

There are 2 large semicircles = 1 large circle

There are 2 small semicircles = 1 small circle

There is 1 rectangle.

Find the Area of each shape above and then find their sum.

1) Large Circle: A = πr²,    d = 10 --> r = 10/2 = 5

                     A = π(5)²

                        = 25π

2) Small Circle: A = πr² ,    d = 2  --> r = 2/2 = 1

                     A = π(1)²

                        = π

3) Rectangle: A = length × width,     L = 10  w = 2

                      A = 10 × 2

                         = 20

Total = Large + Small + Rectangle

         = 25π   +    π      +  20

         = 26π + 20

You might be interested in
The equation for the pH of a substance is pH = –log[H+], where H+ is the concentration of hydrogen ions. Which equation models t
Zanzabum

Answer:  [H+] = 10^-7.2

Step-by-step explanation:

Given that the PH of the solution = 7.2

Using the formula pH = –log[H+]. To get the H+ concentration from the pH, raise both sides by the base of 10. Then we have

10^ -pH = H+. with pH of 7.2,

Thus the answer to this problem is

[H+] = 10^-7.2

8 0
3 years ago
ANSWER ASAP WILL GIVE BRAINLIEST! 30 POINTS!!
podryga [215]

Answer:

y=|x-1|-1

Step-by-step explanation:

hope that helps :)

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
6 0
3 years ago
What is 1/16 times 3​
Lena [83]

Answer:

\bold{\frac{3}{16} }

Explanation:

1 / 16 (3)

= (1 / 16) (3 / 1)

= (1)(3) / (16)(1)

= 3 / 16

4 0
3 years ago
Somthing ab a mark up price, idrk tbh
gregori [183]

Since they reduced the markup price, or higher price, by 10%, the new markup price is 20% over the manufacturer price.

3 0
3 years ago
Other questions:
  • The sum of a number and 9 is -30
    6·1 answer
  • Explain how the identity property in the problem, 5/6 (1) = 1(5/6) = 5/6 is the same with any rational number.
    15·1 answer
  • A bag contains 8 blue marbles, 6 green marbles, 12 yellow marbles, and 10 orange marbles. A marble is drawn at random from the b
    14·1 answer
  • Math help, brainly i don't wanna write more words
    14·2 answers
  • A trunk can carry up to 207 kilograms of cargo. A brick has a mass of 4 kilograms. What is the maximum number of bricks the truc
    13·1 answer
  • If f(x) = 4x + 12x and g(x) = 5x - 1, find (f + g)(x).
    15·1 answer
  • -2 (x + 3z) + 4x - 3y + 2z​
    5·2 answers
  • What is the value of the expression 4 Superscript 4?
    5·2 answers
  • Which three lengths could be the lengths
    14·1 answer
  • Joshua's assignment this weekend is to read a book with seventy-four pages. On Saturday he read thirty pages. How many pages doe
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!