Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
Answer:
5< 10x -3
add like terms first
make sure X's are on one side and numbers on the other
Answer:
shorter piece = 6. longer piece = 12
Step-by-step explanation:
short piece = s
long piece = l
l+s= 18
l= 6+s , substitute
6+s+s = 18
6+2s= 18
2s= 18-6
2s= 12
s=12/2
s= 6= shorter piece
l= 6+s
l= 6+6= 12 = longer piece
Answer:
LOL
Step-by-step explanation:
