Hello!
To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w
To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.
2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24
Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.
Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.
As our final answer, the width of the pool is 16 feet, and the length is 24 feet.
Hope this helps!
Answer:
Step-by-step explanation:
2 m 30 cm
2 m 60 cm
+
_________
4m 90cm
Answer:
the average of this new list of numbers is 94
Step-by-step explanation:
Hello!
To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96
for the first list

for the new list

To solve this problem consider the following
1.X is the average value of the second list
2. We will assign a Y value to the sum of the numbers a, b, c.
a + b + c = Y to create two new equations
for the first list

solving for Y
Y=(90)(4)-80=280
Y=280=a+b+c
for the second list


the average of this new list of numbers is 94
Answer:x>2
Step-by-step explanation:
4x/4>8/4