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EastWind [94]
3 years ago
8

What would earth be like without the moon?

Physics
2 answers:
sleet_krkn [62]3 years ago
8 0
<span>Earth without its moon would be a very different world indeed. No eclipses. Smaller tides. But the biggest change would be in the length of Earth’s day.</span>
maxonik [38]3 years ago
6 0
1.       Nights would be much, much darker. The next brightest object in the night sky is Venus. But it still wouldn't be enough to light up the sky. A full moon is nearly two thousand times brighter than Venus is at its brightest.

2.       Without the moon, a day on earth would only last six to twelve hours. There could be more than a thousand days in one year! That's because the Earth's rotation slows down over time thanks to the gravitational force -- or pull of the moon -- and without it, days would go by in a blink.

3.       A moonless earth would also change the size of ocean tides -- making them about one-third as high as they are now. 

4.       Forget about seeing any lunar eclipses -- or any solar eclipses -- without the moon, there would be nothing to block the sun.

5.       Without a moon the tilt of our earth's axis would vary over time. This could create some very wild weather. Right now, thanks to our moon, our axis stays tilted at twenty-three point five degrees. But without the moon the earth might tilt too far over or hardly tilt at all leading to no seasons or even extreme seasons. 

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A boy is running to the east and jumps into a stationary boat in a lake. Once the boy lands in the boat, the boat moves to the e
Hunter-Best [27]
<span>The initial momentum of the boy is equal to the boy/boat because the final velocity of the boat is less than the initial velocity of the boy.</span>
4 0
3 years ago
What are the three ways to accelerate?
Nookie1986 [14]

Answer:

There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.

Explanation:

5 0
3 years ago
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A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise
kiruha [24]

Answer:

h_m=25.8\ m

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=\frac{v_o^2}{2g}

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}

\mathbf{h_m=25.8\ m}

6 0
3 years ago
If a hydrogen atom has its electron in the n= 4 state, how much energy in eV is needed to ionize it?
ololo11 [35]

Answer:

Explanation:

Energy of electron in n = 4 state

= - 13.6/4² =- 0.85 eV

So energy needed to extract it from atom = .85 eV.

4 0
3 years ago
Two long, parallel wires separated by 3.50 cm carry currents in opposite directions. The current in one wire is 1.55 A, and the
vaieri [72.5K]

Answer:

Therefore,

The magnitude of the force per unit length that one wire exerts on the other is

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

Explanation:

Given:

Two long, parallel wires separated by a distance,

d = 3.50 cm = 0.035 meter

Currents,

I_{1}=1.55\ A\\I_{2}=3.15\ A

To Find:

Magnitude of the force per unit length that one wire exerts on the other,

\dfrac{F}{l}=?

Solution:

Magnitude of the force per unit length on each of @ parallel wires seperated by the distance d and carrying currents I₁ and I₂ is given by,

\dfrac{F}{l}=\dfrac{\mu_{0}\times I_{1}\times I_{2}}{2\pi\times d}

where,

\mu_{0}=permeability\ of\ free\ space =4\pi\times 10^{-7}

Substituting the values we get

\dfrac{F}{l}=\dfrac{4\pi\times 10^{-7}\times 1.55\times 3.15}{2\pi\times 0.035}

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

Therefore,

The magnitude of the force per unit length that one wire exerts on the other is

\dfrac{F}{l}=2.79\times 10^{-5}\ N/m

7 0
3 years ago
Read 2 more answers
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