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Novosadov [1.4K]
3 years ago
6

A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise

Physics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

h_m=25.8\ m

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=\frac{v_o^2}{2g}

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}

\mathbf{h_m=25.8\ m}

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A zero-order reaction has a constant rate of 2.30×10−4 M/s. If after 80.0 seconds the concentration has dropped to 1.50×10−2 M,
dolphi86 [110]

Answer:

Initial concentration of the reactant = 3.34 × 10^(-2)M

Explanation:

Rate of reaction = 2.30×10−4 M/s,

Time of reaction = 80s

Final concentration = 1.50×10−2 M

Initial concentration = Rate of reaction × Time of reaction + Final concentration

= 2.30×10−4 M/s × 80s + 1.50×10−2 M = 3.34 × 10^(-2)M

Initial concentration = 3.34 × 10^(-2)M

6 0
3 years ago
What process takes solid CO2 from a solid to a gas? A) boiling B) melting C) sublimation D) vaporization
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3 years ago
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Vlada [557]

Answer:

friction

Explanation:

Her brakes will squeak and possibly slide or skid on concrete due to her brakes.

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5 0
3 years ago
The average depth of Indian Ocean is about 3000m.Calculate the fractional compression. ▲v/v, of water at the bottom of the ocean
Klio2033 [76]

Answer:

∴ fractional compression = 1.34 × 10⁻²

Explanation:

given,

depth of Indian ocean = 3000 m

Bulk modulus of the water = 2.2 x 10⁹ N/m²

We know,

P = P₀ + ρgh

P₀ is the atmospheric pressure

P₀ = 10⁵ N/m²

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P = 10⁵ + 1000 × 9.8 × 3000 = 2.94 × 10⁷ N/m²

using formula,

B = P/{-∆V/V}

B is bulk modulus and { -∆V/V} is the fractional compression

\dfrac{-\Delta V}{V} = \dfrac{2.94 \times 10^7}{2.2 \times 10^9}

\dfrac{-\Delta V}{V} =1.34 \times 10^{-2}

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7 0
3 years ago
A car accelerates ( speeds up) uniformly from 5 m/s * t * o 15 m/s in 2 seconds, calculate the car's acceleration?
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