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The radius of the curved road at the given condition is 54.1 m.
The given parameters:
- <em>mass of the car, m = 1000 kg</em>
- <em>speed of the car, v = 50 km/h = 13.89 m/s</em>
- <em>banking angle, θ = 20⁰</em>
The normal force on the car due to banking curve is calculated as follows;
The horizontal force on the car due to the banking curve is calculated as follows;
<em>Divide </em><em>the second equation by the first;</em>
Thus, the radius of the curved road at the given condition is 54.1 m.
Learn more about banking angle here: brainly.com/question/8169892
answers:
m2 = 1.05 kg and m1 = 4.75 kg
Explanation:
the gravitational force is given by:
Fg = Gm1×m2/(r^2)
9.20×10^-9 = [(6.67×10^-11)×(m1×m2)]/[(19×10-2)^2]
(m1×m2) = 4.98 kg^2
m1 = 4.98/m2 kg
but we given that:
m1 + m2 = 5.80 kg
4.98/m2 + m2 = 5.80
4.98 + (m2)^2 = 5.80×m2
(m2)^2 - 5.80×m2 + 4.98 = 0
by solving the quadratic equation above:
m2 = 4.75 kg or m2 = 1.05 kg
due to that from the information, m2 has a lighter mass, then m2 = 1.05 kg.
then m1 = 5.80 - 1.05 = 4.75 kg.
There is zero net force required to keep an object moving, even in the same direction. This is because the inertia only depends on the mass of the object moving, not the speed. Therefore, the answer would be none.