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Artyom0805 [142]
3 years ago
12

A boy is running to the east and jumps into a stationary boat in a lake. Once the boy lands in the boat, the boat moves to the e

ast. Which best compares the initial momentum of the boy with the final momentum of the boy/boat system?
Physics
1 answer:
Hunter-Best [27]3 years ago
4 0
<span>The initial momentum of the boy is equal to the boy/boat because the final velocity of the boat is less than the initial velocity of the boy.</span>
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An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. What is the radius of the circ
FromTheMoon [43]
Object Motion: 25 m/s

Circumference of Circle: 
1/4 Circumference of Circle in 1 second = 25 meters
25 meters times 4 = Circumference of Circle 
Circumference = 100 meters

Formula to Find Circumference of Circle: (work opposite)
C = 2<span>πr

100 = </span>2πr          divided
100/2π = r         simplify
50/π = r         (exact radius)

Answer:
50/π meters = r         (exact radius)

4 0
3 years ago
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Which of the following is NOT a layer of the Sun?
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It depends when you look at a pichture it could possibly help.
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4 years ago
An ice skater has a moment of inertia of 5.0 kgm2 when her arms are outstretched. at this time she is spinning at 3.0 revolution
givi [52]
With arms outstretched,
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Assume that the same torque drives the rotational motion at a moment of inertia of 2.0 kg-m².
If u = new rotational speed (rad/s), then
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7 0
4 years ago
A horizontal circular curve on a highway is designed for traffic moving at 60 km/h. If the radius of the curve is 150 m, and if
KengaRu [80]

Answer:

The value of  the correct angle of banking for the road is \theta = 67.76 °

Explanation:

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v = \sqrt{r g \tan \theta}

v^{2} = r g \tan \theta

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\tan \theta = \frac{60^{2} }{(150)(9.81)}

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Therefore the value of  the correct angle of banking for the road is \theta = 67.76 °

4 0
3 years ago
. A 13-g goldfinch has a speed of 8.5 m/s. What is its kinetic energy?
lesya692 [45]
PLEASE PRESS THE “Thanks!” BUTTON! :)
13 g —> 0.013 kg
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KE = 1/2(0.013)(8.5)^2
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