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3 years ago

Help Fast!!! What is 65 divided by 2,210 in a number not percentages or a fraction.

Mathematics

1 answer:

vlabodo [156]3 years ago

6 0

Answer:

0.02941176...

— Used a calculator for this, so it is guarantied correct! Hope this helps. Brainliest appreciated (and very much needed)

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How to set up this problem

HACTEHA [7]

Answer:

The son is five years old

Step-by-step explanation:

Let the son's age be x

A man is five as old as his son, 5x

In five years, he would be three times as old as his son

In five years: son would be x+5

Father 5x+5

3(x+5)=5x+5

3x+15=5x+5

Collect like terms

15-5=5x-3x

10=2x

Divide by 2

10/2=2x/2

x=5

The son is five years old

5 0

3 years ago

If you solve this for me I’ll love you forever (but seriously I need the answer ASAP)

mash [69]

Description:

This will be no solution because when we add 10 to both sides of the equation then simplify it. After that we will subtract 6 from both sides. It will give us no solution. For more info please see the attachment.

Answer: No solution

Hope this helps.

8 0

3 years ago

Read 2 more answers

NEED HELP ASAP!!!!!!!!!!

Alona [7]

Answer:

i dont know what your asking

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

3 years ago

Can I get some help with proofs? Picture is attached

aleksandr82 [10.1K]

Give a reason for each step of the proof.

Given: <1 and <2 are complimentary

<1 is congruent to <3,

<2 is congruent to <4

Prove: <3 and <4 are complimentary

Statements: Reasons:

1. <1 and <2 are complimentary 1.Given

2. m<1 + m<2=90* 2.DEFINITION OF COMPLEMENTARY ANGLES

3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______

4. m<1=m<3, m<2=m<4 4.DEFINITION OF CONGRUENT ANGLES_

5. m<3 + m<2=90* 5. SUBSTITUTION PROPERTY (m<1 is replaced by m<3.)

6. m<3 +m<4=90* 6. DEFINITION OF COMPLEMENTARY ANGLES

7. <3 and <4 are complimentary 7. DEFINITION OF COMPLEMENTARY ANGLES

8 0

3 years ago