F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4
Answer:
yes it is
Step-by-step explanation:
Step-by-step explanation:
2527 is the first line so 5 in the box
then 47 so a 4 in that box
top answer row
315 E7 so a 5 in that box.
Answer:
2^6
Step-by-step explanation:
2^2 + 2^4 = 2^6
Answer:
So, the first five terms of the sequence defined by the given recursive function are shown below.
F(1) 0.75 f(2) 1.1 F(3) 1.45 F(4) 1.8 f(5) 2.15
written on plato
Step-by-step explanation: