Question

A ball undergoes uniform acceleration of 2.50 m/s2 (beginning at rest). How far does the ball travel during that 4s time interval?

Answer 1

Answer:

The ball travels a distance of 20 m in the time interval of 4 s

Explanation:

Using s = ut + 1/2at² where s = distance travelled by the ball, u = initial velocity of ball = 0 m/s (since it starts from rest), a = acceleration of the ball = 2.50 m/s² and t = time = 4 s.

Substituting the variables into the equation, we have

s = ut + 1/2at²

s = 0 × 4 s + 1/2 × 2.50 m/s² × (4 s)²

s = 0 + 1/2 × 2.50 m/s² × 16 s²

s = 1/2 × 40 m

s = 20 m

So, the ball travels a distance of 20 m in the time interval of 4 s.