Answer:
(a) 1.16 s
(b)0.861 Hz
Explanation:
(a) Period : The period of a simple harmonic motion is the time in seconds, required for a object undergoing oscillation to complete one cycle.
From the question,
If 1550 cycles is completed in (30×60) seconds,
1 cycle is completed in x seconds
x = 30×60/1550
x = 1.16 s
Hence the period is 1.16 seconds.
(b) Frequency : This can be defined as the number of cycles that is completed in one seconds, by an oscillating body. The S.I unit of frequency is Hertz (Hz).
Mathematically, Frequency is given as
F = 1/T ........................... Equation 1
Where F = frequency, T = period.
Given: T = 1.16 s.
Substitute into equation 1
F = 1/1.16
F = 0.862 Hz
Hence thee frequency = 0.862 Hz
The material can transmit heat by energy transfer through collision of atoms. The elements that has a high ability of transmitting heat within their material are the metals. They are said to have high thermal conductivity. As the metal heats up, because the atoms are closely packed, they easily transfer heat through conduction. For example, copper is used in electrical wirings because it has a high thermal conductivity.
Answer:
P = 200 W
Explanation:
The expression for the power is
P = W / t
the job
W = F d
we substitute
P = F d / t
P = F. v
We apply this equation to our case where the velocity is
v = (5 i + 3j + 6k) m / s
and the force is
F = (10i + 10j +20 k) N
we substitute in the power equation, remember that the scalar product of the unit vectors is
i.i = j.j = k.k = 1 and the other products are zero
P = 10 5 + 10 3 + 20 6
P = 200 W
<span>Humberto builds two circuits using identical components,
and then adds components to each circuit.
Circuit 1:
A series circuit with three lightbulbs.
Then add three more lightbulbs in series.
Circuit 2:
A parallel circuit with three lightbulbs
Then add two more lightbulbs on new branches
in parallel with each original bulb.
After adding the new lightbulbs in Circuit 1:
-- the voltage across each of the original bulbs is less,
-- the current through the whole series circuit is less,
-- the original three bulbs shine dimmer than before, and
-- the total power delivered from the battery is less.
-- The battery lasts longer.
After adding the new lightbulbs in Circuit 2:
</span>-- the voltage across each of the original bulbs is doesn't change,
-- the current through each original bulb doesn't change,
-- the original three bulbs shine just as bright as before,
-- the total currrent drawn by the circuit, and the total current
delivered by the battery, increases, and
-- the total power delivered from the battery increases.
-- The battery runs down sooner.
