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Stella [2.4K]
2 years ago
13

After Thanksgiving, Kevin and Gamal use the turkey’s wishbone to make a wish. If Kevin pulls on it with a force 0.17 N larger th

an the force Gamal pulls with in the opposite direction and the wishbone has a mass of 13 g, what is the wishbone’s initial acceleration?
Physics
1 answer:
Elena-2011 [213]2 years ago
8 0

The initial acceleration of the wishbone is 13.1 m/s².

<h3></h3><h3></h3><h3>Acceleration:</h3>

This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²

To calculate the acceleration of the wishbone, we use the formula below.

⇒ Formula:

  • F' = ma........................... equation 1

⇒ Where:

  • F' = Net force between Kevin and Gamal
  • m = mass of the wishbone
  • a = acceleration of the wishbone

⇒ make a the subject of the equation

  • a = F'/m....................... Equation 2

From the question,

⇒ Given:

  • F' = 0.17 N
  • m = 13 g = 0.013 kg

⇒ Substitute these values into equation 2.

  • a = 0.17/0.013
  • a = 13.1 m/s²

Hence, The initial acceleration of the wishbone is 13.1 m/s².

Learn more about acceleration here: brainly.com/question/605631

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Answer:  (x - 4)² + (y - 7)² = 9

<u>Explanation:</u>

The equation of a circle is: (x - h)² + (y - k)² = r²    where

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  • r is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

     -4y = -3x - 1

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              m=\dfrac{3}{4}      -->      m_{\perp}=-\dfrac{4}{3}

y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}

Use substitution to find the point of intersection:

x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3

Input h = 4, k = 7, and r = 3 into the circle equation:

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