Point p and point Q has to be the same point
4 consecutive integers : (x), (x + 1), (x + 2), (x + 3)
x + x + 1 + x + 2 + x + 3 = 114...combine like terms
4x + 6 = 114....subtract 6 from both sides
4x = 114 - 6
4x = 108...divide both sides by 4
x = 108/4
x = 27
x + 1 = 27 + 1 = 28
x + 2 = 27 + 2 = 29
x + 3 = 27 + 3 = 30
so ur 4 numbers are : 27, 28, 29, 30
the answer to this question is -8
Answer:
(0,0) doesn’t show a rate of 12 messages per hour
I’m confused about the rest please elaborate
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
Let x be that missing number
One third of it is x/3
One-ninth of it is x/9
Multiply x/3 and x/9
● (x/3)*(x/9) = (x^2/27)
● (x^2/27) = 108
Multiply both sides by 27
● (x^2/27)*27 = 108*27
● x^2 = 2916
● x = √(2,916) or x = -√(2,916)
● x = 54 or x = -54
So there are two possibilities 54 and -54.
