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coldgirl [10]
3 years ago
5

2x A= 24

Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

Option A 12 is the answer

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What does c equal in thus equation I don't know for the life of me help is deeply appreciated 4(3+c)+c=c+4
Shkiper50 [21]

Answer:

-2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4(3+c)+c=c+4

(4)(3)+(4)(c)+c=c+4(Distribute)

12+4c+c=c+4

(4c+c)+(12)=c+4(Combine Like Terms)

5c+12=c+4

5c+12=c+4

Step 2: Subtract c from both sides.

5c+12−c=c+4−c

4c+12=4

Step 3: Subtract 12 from both sides.

4c+12−12=4−12

4c=−8

Step 4: Divide both sides by 4.

4c

4

=

−8

4

c=−2

5 0
4 years ago
What is the solution to the linear equation?
DIA [1.3K]

Answer:

the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2

Step-by-step explanation:

We need to solve the linear equation

4b + 6 = 2 - 6 +4

Adding constants

4b + 6 = 0

Adding -6 on both sides

4b + 6 -6 = 0 -6

4b = -6

Dividing with 4 on both sides

4b/4 = -6/4

b = -2

So, the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2

8 0
3 years ago
which is the rationalized form of the expression the square root of x divided by the square root of x +the square root of 7
Ilya [14]

Answer:

I assume your goal is to rationalize the denominator -

So you need to multiply the denominator by its conjugate.

So we have:

\frac{\sqrt{x} }{\sqrt{x}-\sqrt{7} } *\frac{\sqrt{x} +\sqrt{7} }{\sqrt{x} +\sqrt{7}}

->

\frac{x-\sqrt{7}\sqrt{x} }{x-7}

gg

8 0
3 years ago
Could someone pls explain this step by step? Really simplify it pls because I don't understand it at all.
Lunna [17]

Answer:

  • y = 2x -6
  • y = -x +2
  • y = 4/5x -2
  • y = -3/2x +4

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx +b . . . . . where m is the slope, and b is the y-intercept

For these equations, writing them in slope-intercept form means "solve for y." You always do any "solve for ..." problem by undoing the operations that are done to the variable. Addition is undone by adding the opposite. Multiplication is undone by division.

As always, whatever operation we perform on one side of the equal sign must also be performed on the other side. That is how the equal sign remains valid.

__

<h3>a)</h3>

  1/2y = x -3

All we need to do is get rid of the coefficient of y. We can do that by dividing by 1/2, or multiplying by 2. The latter is easier to see, perhaps.

 2(1/2y) = 2(x -3)

  y = 2x +2(-3)

  y = 2x -6

__

<h3>b)</h3>

  x +y = 2

Here, we need to undo the addition of x. We do that by adding (-x) to both sides of the equation.

  -x +x +y = -x +2

  y = -x +2

__

<h3>c)</h3>

  4x -5y -10 = 0

This is a combination of the above operations. We can separate the y-term from the others by either subtracting the others, or adding the opposite of the y-term. We choose the latter, because that will give a positive coefficient for y. Adding 5y to both sides gives ...

  4x -5y +5y -10 = 5y

  5y = 4x -10 . . . . . . . . simplify and put y on the left

Now, we need to divide by the coefficient of y. We do that to both sides of the equation.

  5y/5 = (4x -10)/5

  y = 4/5x -10/5

  y = 4/5x -2

__

<h3>d)</h3>

  3x = -2y +8

We have a constant with the y-term. To get rid of it, we add its opposite to both sides.

  3x -8 = -2y +8 -8

  3x -8 = -2y

As before, we divide by the coefficient of y:

  (3x -8)/(-2) = (-2y)/(-2)

  -3/2x +4 = y

  y = -3/2x +4

3 0
2 years ago
+ 2h + 5 when g = 3 and h = 6.
Rudik [331]
Is this the whole problem because I don’t see a “g”
Anywhere I’m the problem
5 0
3 years ago
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