The frequency of note C3 is 131
.
<u>Explanation:</u>
Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.
And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.
Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

Thus,

So the frequency of note C3 is 131
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Answer:
final temperature is 469.71 K = 196.71 °C
Explanation:
Given data
volume V = 1010 cm3 = 0.00101 m³
temperature = 20.7°C = 20.7 + 273 = 293.7 K
pressure P1 = 1.04 x 10^5 Pa
volume = 1570 cm3
pressure P2 = 1.07 x 10^5 Pa
to find out
number of moles of oxygen and final temperature
solution
we know that for ideal gas
PV = nRT
put here all value to get n
R gas constant = 8.314472 J/mol−K and T = 293.7 K and V = 0.00101 m³
and P = 1.04 x 10^5
so n = ( 1.04 x 10^5 × 0.00101 ) / ( 8.314472 × 293.7 )
n = 0.043015 moles
and
now we use equation
P1V1 /T1 = P2V2 / T2
1.04 x 10^5 × 1010 / 293.7 = 1.07 x 10^5 × 1570 / T2
T2 = 49338663 / 105040 = 469.71 K
so final temperature is 469.71 K = 196.71 °C
The answer would be....
Explored the deepest known ocean trench.
I believe the answer is D