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AlekseyPX
3 years ago
14

In a lab experiment, 5300 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to do

uble every 10 hours. How many bacteria would there be after 12 hours, to the nearest whole number?
Mathematics
1 answer:
alex41 [277]3 years ago
4 0

Answer:

yooooo

Step-by-step explanation:

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Which two types of income does a person in a full-time sales job usually receive?
katovenus [111]

Answer:

hourly pay & commission

Step-by-step explanation:

Full time sales jobs typically pay their employees an hourly pay and then a commission on what they sell.

8 0
3 years ago
Read 2 more answers
Is 143 and 63 relatively prime numberd
Igoryamba
Yes 143 and 63 are relatively prime because they have no prime factors in common   

brainliest answer please?
4 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Please help me with this D:
I am Lyosha [343]
Yes, because 120 - 36 = (120\times 36) - 4236 = 84

Hope that helped :D
8 0
3 years ago
140 degrees decreased by 65%
BaLLatris [955]
Hey there! 
<span>Here are the steps involved: 
</span>
1.Change 65% into a decimal. Move the decimal two places to the left and you get 0.65.

2. Multiply 0.65 by 50.
<span>140 x 0.65 = 91.

3. Since you are decreasing 140 by 65%, subtract 140 by 91. 
140-91= 49


</span><span>(If you feel that my answer has helped you, please consider rating it and giving it a thank you! Also, feel free to make the best answer, the brainliest answer!)
</span>
<span>Thank you! :D</span>


7 0
3 years ago
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