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r-ruslan [8.4K]
3 years ago
14

PLEASE HELPPPP

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

A rhombus is equilateral: all of its sides are of the same length. But it is never equiangular. A rhombus by definition has two opposite sets of equal angles. It can never, therefore, be equiangular.

Step-by-step explanation:

Hope this helps

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Solve for x:
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Answer:

Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.

The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.

4 0
3 years ago
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Find the point on the line y = 2x +1 that is closest to the point (5, 2).
ELEN [110]
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3 years ago
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^n-x, where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

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3 years ago
142 x 12 in algorithm standard<br> and in area model
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Answer:

0333

Step-by-step explanation:

00

000

0000

1112222

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