Answer:
a)
The analytic expression for p(V) is 
b)
The expression of the work in terms of p0 ,V0,V1 is
![W= \frac{5}{2} P_{0}[V_{0}-V_{0}^{7/5}V_{1}^{-2/5}]](https://tex.z-dn.net/?f=W%3D%20%5Cfrac%7B5%7D%7B2%7D%20P_%7B0%7D%5BV_%7B0%7D-V_%7B0%7D%5E%7B7%2F5%7DV_%7B1%7D%5E%7B-2%2F5%7D%5D)
c)
The change in internal energy of the gas
![\delta U = \frac{5}{2}P_{0}[V_{0}^{7/5}V_{1}^{-2/5}-V_{0}]](https://tex.z-dn.net/?f=%5Cdelta%20U%20%3D%20%5Cfrac%7B5%7D%7B2%7DP_%7B0%7D%5BV_%7B0%7D%5E%7B7%2F5%7DV_%7B1%7D%5E%7B-2%2F5%7D-V_%7B0%7D%5D)
Explanation:
The explanation is shown on the first, second and third
Answer:
A) True, B) False, C) False and D) false
Explanation:
Let's solve the problem using the law of conservation of energy to know if the statements are true or false
Let's look for mechanical energy
Initial
Emo = Ke = ½ k Dx2
Final
Em1= ½ m v12
Emo = Em1
½ k Δx2 = ½ m v₁²
v₁² = k / m Δx²
v₁ = √ k/m Δx
Now let's calculate the speed when it falls
Vfy² = Voy² - 2gy
Vfy² = - 2gy
Vf² = v₁² + vfy²
A) True v₁ = A Δx
.B) False. As there is no rubbing the mechanical energy conserves
.C) False the velocity is proportional to the square root of the height
v2y = v2 √2
. D) false promotional compression speed
Answer:
The flashlight leaves the water at an angle of 51.77°.
Explanation:
if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.
Then, according to Snell's law :
n1×sin(∅1) = n2×sin(∅2)
sin(∅2) = n1×sin(∅1)/n2
= (1.33)×sin(36.2)/(1.0)
= 0.7855055×379
∅2 = 51.77°
Therefore, the flashlight leaves the water at an angle of 51.77°.
The most appropriate answer is C !! the Sun !!