All categories

3 years ago

What is the energy of work done lifting 2kg mass rocket to a height of 130 m

Physics

2 answers:

GalinKa [24]3 years ago

4 0

Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm

Dominik [7]3 years ago

3 0

Work done to lift the mass is given by

W = mgH

here we know that

m = mass = 2 kg

g = acceleration due to gravity = 9.8

H = height = 130 m

now using the above equation we can write

$U = 2* 9.8 * 130$

$U = 2548 J$

so the energy required to do the work is 2548 J

You might be interested in

a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe

e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by $0.5I\omega^{2}$ where I is moment of inertia which is given by $mr^{2}$ and here m is mass, r is radius. Also, $v=\omega r$ hence making \omega the subject then $\omega=\frac {v}{r}$ where v is the velocity.

Rotational kinetic energy= $0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}$

This is same as the formula for translational kinetic energy which is given by $0.5mv^{2}$

Therefore, total kinetic energy= $0.5mv^{2}+0.5mv^{2}=mv^{2}$

Substituting m with 2 kg and v with 6 m/s then total energy will be $2\times 6^{2}=72 J$

7 0

3 years ago

when you order clothes, does the sweater has to be longer than your shirt to fit you just like the shirt?

Troyanec [42]

Answer:

Yes.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

8 0

3 years ago

Rewrite the following sentence in the negative form >Each library contains 3000 brand new books

otez555 [7]

None of the libraries have up to 3000 brand new books

3 0

2 years ago

A ball with a mass of 2.89 kg bounces off of the ground. Just before it hits the ground, its velocity is 6.00 m/s in the downwar

White raven [17]

Answer:

30.46 kgm/s

Explanation:

According to conservation law of momentum, the magnitude of the impulse J that the ground gave the ball equals to the change in momentum of the ball before and after it hits the ground.

Before the hit, the ball velocity is 6m/s, so its momentum is 6 * 2.89 = 17.34 kgm/s

After the hit, the ball velocity is -4.54 m/s in the opposite direction, so its momentum is 2.89*(-4.54) = -13.12 kgm/s

So the change of momentum, and also the impulse is

17.34 - (-13.12) = 30.46 kgm/s

3 0

3 years ago

When object 1 came into contact with object 2, object 2 got warmer. what can be concluded about the objects before they came int

luda_lava [24]

The statement that is true regarding the objects is that object 1 had faster-moving particles, which is option 2. Details about matter can be found below.

<h3>What is matter?</h3>

Matter can be defined as any particle that has weight and occupies space.

Certain particles are present in the different states of matter. According to this question, when object 1 came into contact with object 2, object 2 got warmer.

This suggests that the particles in the object 1 is moving faster due to an increase in temperature.

Learn more about matter at: brainly.com/question/4513444

#SPJ1

7 0

2 years ago