All categories

4 years ago

Which phenomenon support only the wave theory of light? Check all that apply

Physics

2 answers:

lys-0071 [83]4 years ago

8 0

Answer:

Diffraction and Interference of light support the wave theory of light.

Explanation:

Complete Question

Which phenomena support only the wave theory of light? Check all that apply.

1.reflection

2.refraction

3.diffraction

4.interference

5.photoelectric effect

Solution

There are two theories/schools of thoughts that light possesses wave and particle properties.

The wave properties of light explain that light is made as a result of interactions of electric and magnetic fields, hence, light is regarded as an electromagnetic wave that propagates without the need for a material medium and moves in a direction perpendicular to the direction of the oscillations or direction of the cause/source of the light waves.

Properties that support the wave properties of light are diffraction (ability to navigate or bend around obstacles) and Interference (two light waves can combine or superimpose to form a single resultant light wave with amplitude greater, lower or equal to the amplitudes of the two constituting light waves).

Hope this Helps!!!

alexdok [17]4 years ago

8 0

Answer:

The question may not be a fully complete question, as it should provide a list of options to pick correctly from.

However, "diffraction and interference" are phenomenon that support the wave theory of light.

Explanation:

A wave orchestrate the transfer of energy from one point to another. Light was made up of tiny particles usually electromagnetic radiation of any wavelength.

Diffraction in light wave causes the wave to have interference with itself as a result of hindrance faced by part of the wavefront while travelling. Diffraction of waves could be noticed when waves spread after they pass through small openings, which depends on the size of the wavelength of light compared to the opening, or obscured by bending around small obstacles. An example of diffraction in light wave can be observed in X-ray.

Wave interference occurs when two waves collides while traveling along the same medium usually they may not originate from the same source. Wave interference can be destructive interference, or constructive interference.

You might be interested in

A pool ball moving 1.83 m/s strikes an identical ball at rest. Afterward, the first ball moves 1.15 m/s at a 23.3° angle. What i

Oksi-84 [34.3K]

Answer:

v_{1fy} = - 0.4549 m / s

Explanation:

6 0

3 years ago

A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate

Olegator [25]

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

$E_{A}=E_{B}$

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

$E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}$

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

$E_{B}=m*g*h+\frac{1}{2}*m*v^{2}$

Therefore we will have the following equation:

$(6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s]$

The kinetic energy can be easily calculated by means of the kinetic energy equation.

$KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J]$

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

$E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s]$

5 0

3 years ago

A car with a mass of 2.0 * 10^3 kg is traveling at 15 m/s. what is the momentum of the car?

Allushta [10]

Hello,

Your answer to this problem is 400/3

Hope this helps!

3 0

3 years ago

What study did james e hansen focus on

Brut [27]

James E. Hansen studied climate change

6 0

2 years ago

Read 2 more answers

When two objects with electrical charges interact, which affect the strength of that interaction?

noname [10]

The two objects with electrical charges interact, which affect the strength of that interaction <span>amount of charge. The answer is letter A. The rest of the choices do not answer the question above.</span>

6 0

3 years ago