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3 years ago

Sampling error equals to half the width of a confidence interval. true or false

Mathematics

1 answer:

tresset_1 [31]3 years ago

8 0

The answer is TRUE.

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Show that (x-5) is a factor of x^3-3x^2-13x+15

mario62 [17]

Answer:

sorry not in that grade

Step-by-step explanation:

6 0

3 years ago

What is y - 2 = -3 [x-7] written in standard form

Akimi4 [234]

Y=-3x+23

distribute -3, get y alone (add 2 to both sides)

3 0

3 years ago

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

8 0

3 years ago

Read 2 more answers

Suling bought 3meters of ribbons she used 5/6meter to make a bow find the length of the ribbon left

Ostrovityanka [42]

Subtract the portion used from the whole.

= 3 m - 5/6m
must have common denominators
= (3*6)/(1*6) - 5/6
= 18/6 - 5/6
= 13/6 m
= 2 1/6 m

ANSWER: 2 1/6 meters left

Hope this helps! :)

5 0

3 years ago

Solve 3x2 + 4x = −5.

Alla [95]

Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

a=3
b=4
c=5

x= $\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}$
x= $\frac{-4+/- \sqrt{16-60} }{6}$
x= $\frac{-4+/- \sqrt{-44} }{6}$
x= $\frac{-4+/- 2\sqrt{-11} }{6}$
remember that√-1=i
x= $\frac{-4+/- 2i\sqrt{-11} }{6}$
x= $\frac{-2+/- i\sqrt{-11} }{3}$

x= $\frac{-2+ i\sqrt{-11} }{3}$ or x= $\frac{-2- i\sqrt{-11} }{3}$

4 0

3 years ago