Answer:
0.75 mg
Step-by-step explanation:
From the question given above the following data were obtained:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Amount remaining (N) =.?
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Number of half-lives (n) =?
n = t / t₁/₂
n = 6/6
n = 1
Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Number of half-lives (n) = 1
Amount remaining (N) =.?
N = 1/2ⁿ × N₀
N = 1/2¹ × 1.5
N = 1/2 × 1.5
N = 0.5 × 1.5
N = 0.75 mg
Thus, 0.75 mg of the sample is remaining.
Answer:
NRN
Step-by-step explanation:
The correct answer for the exercise shown above, is the first option (Option A), which is:
A. <span>(1+1/18)^18
The explanation is shown below:
1- You have that the number e is an irrational number, therefore, its value is aproximated:
e=2.7182
2- You have the following expressions:
</span>(1+1/18)^18=2.6464
<span>(1+1/17)^17=2.6424
</span><span>(1+1/16)^16=2.6379
</span><span>(1+1/15)^15=2.6328
Therefore the value of the expression that is closest to e is the Option A.</span>
Answer:
Therefore the rate change of height is 
m/s.
Step-by-step explanation:
Given that a vertical cylinder is leaking water at rate of 4 m³/s.
It means the rate change of volume is 4 m³/s.
The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.
The height of the cylinder be h(say).
The volume of a cylinder is 
Differentiating with respect to t.
Putting the value 
The rate change of height does not depend on the height.
Therefore the rate change of height is m/s.
