Answer:
![y=-67.5[cos(\frac{\pi}{15}t)-1]](https://tex.z-dn.net/?f=y%3D-67.5%5Bcos%28%5Cfrac%7B%5Cpi%7D%7B15%7Dt%29-1%5D)
Step-by-step explanation:
We can start solving this problem by doing a drawing of London Eye. (See attached picture).
From the picture, we can see that the tourists will start at the lowest point of the trajectory, which means we can make use of a -cos function. So the function will have the following shape:
![y=-Acos(\omega t)+b](https://tex.z-dn.net/?f=y%3D-Acos%28%5Comega%20t%29%2Bb)
where:
A=amplitude
= angular speed.
t= time (in minutes)
b= vertical shift.
In this case:
A= radius = 67.5 m
![\omega=2\pi f](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f)
where the frequency is the number of revolutions it takes every minute, in this case:
![f=\frac{1}{30} rev/min](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B30%7D%20rev%2Fmin)
so:
![\omega=2\pi (\frac{1}{30})](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20%28%5Cfrac%7B1%7D%7B30%7D%29)
![\omega=\frac{\pi}{15} rad/min](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B%5Cpi%7D%7B15%7D%20rad%2Fmin%20)
and
b= radius, so
b=A
b=67.5m
so we can now build our equation:
![y=-67.5cos(\frac{\pi}{15} t)+67.5](https://tex.z-dn.net/?f=y%3D-67.5cos%28%5Cfrac%7B%5Cpi%7D%7B15%7D%20t%29%2B67.5)
which can be factored to:
![y=-67.5[cos(\frac{\pi}{15}t)-1]](https://tex.z-dn.net/?f=y%3D-67.5%5Bcos%28%5Cfrac%7B%5Cpi%7D%7B15%7Dt%29-1%5D)
You can see a graph of what the function looks like in the end on the attached picture.
Answer: a. 30 000
b. £3.00
c.10 000
Step-by-step explanation:
Answer:
George's integer is 53
Step-by-step explanation:
Opposite of a is -a
Similarly, -53 is the opposite of 53
That is 46.25 years which is 46 years and 3 months (since 3/12 = 0.25)
So it will be December
To find y, divide the first equation by 2.
y = 4
To find x, use that value for y in the second equation. Add 4, then divide by 2.
15·4 = 2x -4
60 +4 = 2x
64/2 = x = 32
The solution is (x, y) = (32, 4).