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Soloha48 [4]
3 years ago
10

Please help me if you can ​

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0

Answer:

8π in

64π mm²

Step-by-step explanation:

The circumference of a circle is equal to 2πr, where r is the radius.

2π(4) = 8π ≈ 25.132

The area of a circle is equal to πr²

π(8)² = 64π ≈ 201.062

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Can someone please help me with this???
tino4ka555 [31]

Answer:

1 cm

Step-by-step explanation:

To solve this problem we can use the Pythagorean theorem. In fact the diagonal of a rectangle is an hypotenuse of a right triangle, while the length is a leg. The width is the other leg

width = √2^2 - (√3)^2 = √4 - 3 = √1 = 1 cm

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3 years ago
Thomas creates the table shown to represent the function ƒ(x) = x2 + 3x - 10. determine the zeros of the equation.
Eddi Din [679]
Answer: A

Explanation: The zeroes of f(x) are the value/s of x such that f(x) = 0. So, we need to find the values of x in the equation f(x) = 0.

Note that

f(x) = 0
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By factoring into binomials, x² + 3x - 10 = (x + 5)(x - 2). Thus, 

x² + 3x - 10 = 0
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4 0
4 years ago
2 and 3 are<br> angles.<br> complementary<br> vertical<br> congruent<br> supplementary
Lapatulllka [165]

Answer:

supplementary

Step-by-step explanation:

Angles 2 and 3 form a straight line.  Straight lines are supplementary

5 0
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PLEASE HELP ASAP !!
wariber [46]

Answer:

     <u>First figure:</u>            954cm^3

     <u>Second figure:</u>      1,508yd^3

     <u>Third figure:</u>

  •          Height= q
  •           Side length = r

     <u>Fourth figure: </u>        726cm^3

Explanation:

<u></u>

<u>A. First figure:</u>

<u>1. Formula:</u>

            \text{Volume of a cylinder}=\pi \times radius^2\times length

<u>2. Data:</u>

  • radius = 9cm / 2 = 4.5cm
  • length = 15 cm

<u>3. Substitute in the formula and compute:</u>

          Volume=\pi \times (4.5cm)^2\times (15cm)\approx 954cm^3\approx 954cm^3

<u>B. Second figure</u>

<u>1. Formula: </u>

       \text{Volume of a leaned cylinder}=\pi \times radius^2\times height

<u>2. Data:</u>

  • radius = 12yd
  • height = 40 yd

<u>3. Substitute and compute:</u>

      Volume=\pi \times (12yd)^2\times (40yd)\approx 1,507.96yd^3\approx 1,508yd^3

<u></u>

<u>C) Third figure</u>

a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u>  </u><u>q  </u>.

The apex is the point where the three leaned edges intersect each other.

b) The side length is the measure of the edge of the base, i.e.<u>  r </u><u> </u>.

When the base of the pyramid is a square the four edges of the base have the same side length.

<u>D) Fourth figure</u>

<u>1. Formula</u>

The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

          Volume=(1/3)B\times H

<u>2. Data: </u>

  • height: H = 18cm
  • side length of the base: 11 cm

<u>3. Calculations</u>

a) <u>Calculate the area of the base</u>.

The base is a square of side length equal to 11 cm:

          \text{Area of the base}=B=(11cm)^2=121cm^2

b) <u>Volume of the pyramid</u>:

         Volume=(1/3)B\times H=(1/3)\times 121cm^2\times 18cm=726cm^3

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