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eimsori [14]
2 years ago
5

A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the

width of the rectangle.
Mathematics
1 answer:
STALIN [3.7K]2 years ago
7 0

Answer:

The width of rectangle is W=\frac{108}{13}\ cm  or  8\frac{4}{13}\ cm

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

P=2(L+W)

where

L is the length of rectangle

W is the width of rectangle

we have

P=26\ cm\\L=(x+4)\ cm\\W=12x\ cm

substitute

26=2(x+4+12x)

solve for x

26=2(13x+4)

26=26x+8

26x=26-8

26x=18

x=\frac{18}{26}

simplify

x=\frac{9}{13}

<em>Find the width of rectangle</em>

W=12x\ cm

substitute the value of x

W=12(\frac{9}{13})=\frac{108}{13}\ cm

Convert to mixed number

\frac{108}{13}\ cm=\frac{104}{13}+\frac{4}{13}=8\frac{4}{13}\ cm

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Answer:

Step-by-step explanation:

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2 years ago
Angeline bought s yards of satin fabric priced at $8.09 per yard, and c yards of cotton fabric priced at $3.79 per yard. Use an
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Answer:

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y= 30.32 + 40.45

y = 70.77

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3 years ago
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Answer:

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Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

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<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

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<u>Conclusion</u>:-

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Here. ...the sum of interior angle of triangle is 180° so...

90° + 43° + y = 180°.

133° + y = 180°

y = 180° - 133°

y = 47°

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2 years ago
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