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schepotkina [342]
4 years ago
13

Joy and Cullen put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes after

a certain amount of time (x), in weeks, is shown by the equations below:
Joy: y = 30x + 20
Cullen: y = 20x + 90

After how many weeks will Joy and Cullen have the same amount of money in their money boxes, and what is that amount?



6 weeks, $150
230 weeks, $7
7 weeks, $150
7 weeks, $230
Mathematics
2 answers:
bogdanovich [222]4 years ago
5 0

Answer:

7 weeks, $230

Step-by-step explanation:

i just took the test

Harrizon [31]4 years ago
4 0
The answer would be D. 7 weeks, $230. 

Explanation: y would be the total amount after x weeks. So, to find the answer, simply go through your choices and insert x and y. Both y's for Joy and Cullen have to match up for the answer to be correct. 

For answer D, it looks like: 

Joy: 30(7) + 20 = 230
Cullen: 20(7) + 90 = 230

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Y = 5x + 9 (-2, -3) pls help me
Nuetrik [128]

Answer:

Not a solution.

Step-by-step explanation:

y = 5x + 9

-3 = 5(-2) + 9

-3 = -10 + 9

-3 ≠ -1

The point given is not on the line. It is NOT a solution to the equation.

Hope this helps.

8 0
3 years ago
Solve the percentage problems. b Find the number if 6% of it is 20% of 6
Fed [463]

Answer:

the number is 20

Step-by-step explanation:

6% of x = 20% of 6

0.06x=0.20*6

0.06x=1.20

x=1.20/0.06

x=20

3 0
3 years ago
Can u plz show work?Only need 84
Sonbull [250]

Answer:

Step-by-step explanation:

6 0
3 years ago
What is the best approximation for the circumference of a circle with a diameter of 300 ft?
geniusboy [140]

Hello!

\bf Answer

The best approximation for the circumference is \boxed{ \bf 942~ft.}

______________________________________________________


\bf Explanation

c = 2\pir

r = 300 ÷ 2

r = 150


c = 2 × 3.14 × 150

c = 942

6 0
3 years ago
Read 2 more answers
Look at the rectangle and the square: Ada says that the length of diagonal SQ is two times the length of diagonal OM. Is Ada cor
Musya8 [376]

Answer:

No, she is wrong.

Step-by-step explanation:

A diagonal of square or rectangle is equals to hypotenuse of a triangle. So you can apply Pythagoras Theorem to solve it :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Rectangle,

{qs}^{2}  =  {rs}^{2}  +  {qr}^{2}

{qs}^{2}  =  {16}^{2}  +  {8}^{2}  = 320

qs =  \sqrt{320}  = 17.9 \: inches

Square,

{om}^{2}  =  {lo}^{2}  +  {lm}^{2}

{om}^{2}  =  {8}^{2}  +  {8}^{2}  = 128

om =  \sqrt{128}  = 11.3 \: inches

Given that QS is 17.9 and OM is 11.3. So SQ is not 2 times greater than OM.

17.9 \div 11.3 = 1.58 \: (not \: equals \: to \: 2)

7 0
3 years ago
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