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2 years ago

11

Write an equation in slope-intercept form for a line that passes through the given pair of points. (-6,5), (-9,0)

1 answer:

11111nata11111 [884]2 years ago

4 0

Slope intercept form is y=mx+b because m=slope and b=y-intercept hence "slope intercept form"...

m=deltay/deltax=(0-5)/(-9--6)=-5/-3=5/3 so far we have now:

y=5x/3 +b, using any point, I'll use (-9,0) we can now solve for b or the y-intercept...

0=-9(5)/3 +b

0=-15+b, so b=15 and our line is:

y=5x/3 + 15 or more neatly

y=(5x+45)/3

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2 years ago

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3 years ago

Read 2 more answers

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Murrr4er [49]

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2 years ago

Write the ratio for sin A and cos A. The triangle is not drawn to scale.

Zolol [24]

Option A:

$$ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Solution:

Given data:

AB = 50, BC = 48, AC = 14

To find the value of sin A and cos A:

$$\sin A= \frac{Opposite \ side}{Hypotenuse}$

$$\sin A= \frac{AC}{AB}$

$$\sin A= \frac{14}{50}$

$$\cos A= \frac{Adjacent \ side}{Hypotenuse}$

$$\cos A= \frac{BC}{AB}$

$$\cos A= \frac{48}{50}$

$$\therefore \ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}$

Hence option A is the correct answer.

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3 years ago