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3 years ago

If your employer asked you to select one of these options:

2 answers:

7 0

It would depend on the number of days in the month but the sequence is a geometric one. And it grows very rapidly so I'd pick that, and the sum can be expressed as:

s(n)=a(1-r^n)/(1-r) here a=0.01 (a cent) and r=2 so

s(n)=0.01(1-2^n)/(1-2)

s(n)=-0.01(1-2^n) so just assume a 28 day month, in the first month you will earn

s(28)=-0.01(1-2^28)=$2,684,354.55 Yes that is over two and a half million dollars in the first month :P

On that 28th day you will earn:

a(28)=0.01(2^(28-1))=$1,342,177.28

aev [14]3 years ago

6 0

Well idk option 2 but option 1 should be $2,500 for the first month

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marta [7]

1- FM is 3

we know that FM and FG are radius of the circle. so:
FM =FG

so if we find FG by Pythagorean theorem, we find FM, too

FL (hypotenuse) is 5

HL is 8. GL is half of HL. so GL is 4

now we can use Pythagorean theorem to find FG
$4 {}^{2} + {x}^{2} = {5}^{2} \\ {x}^{2} = {5}^{2} - {4}^{2} \\ {x}^{2} = 25 - 16 = 9 \\ x = \sqrt{9} = 3$

2- x is 40

BAD is half of m DB

ADB is half of m AB

so BAD is 50

and ADB is 90

Then ABD will be:
$180 - (50 + 90) = 180 - 140 \\ = 40$

good luck

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3 years ago

Fiona wants 6 red, 3 green and 3 yellow buttons on her dress. All buttons must be placed along a straight vertical line with no

elixir [45]

The appropriate method to use in solving the given question is permutation. Then, the numbers of ways to arrange the buttons is 1320 ways.

In the given question, the order of arrangement is important, so that the number of ways that Fiona could order the buttons can be determined by permutation method.

i.e $_{n}$ $P_{r}$ = $\frac{n!}{(n - r)!}$

Red 6

Green 3

Yellow 3

Total 12

Since no two neighbouring buttons of the same colour is allowed, then 3 buttons would be arranged at a time.

Thus, n = 12 and r = 3;

$_{12}$ $P_{3}$ = $\frac{12!}{(12 - 3)!}$

= $\frac{12!}{9!}$

= $\frac{12*11*10*9!}{9!}$

= 12 x 11 x 10

$_{12}$ $P_{3}$ = 1320

Therefore the buttons can be arranged in 1320 ways without two neighbors having the same colour.

Visit: brainly.com/question/1408616

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