Answer:
1. $0.48
2. $0.52
3. $0.53
Step-by-step explanation:
12/ $25
24/$46
50/$94
hope this helps
Integrate <span>f ''(x) = −2 + 36x − 12x2 with respect to x:
f '(x) = -2x + (36/2)x^2 - (12/3)x^3 + c. Find c by letting x = 0 and using f(0)=8.
Then f '(0) = -2x + 18x^2 - 4x^3 + c = 18 (which was given).
Then -0 + 0 - 0 + c = 18, so c = 18 and
f '(x) = </span>-2x + 18x^2 - 4x^3 + 18.
Go through the same integration process to find f(x).
A.
2/3A=-24
time both sides by 3/2
A=-72/2
A=-36
B.
20=-B/0.2
times both sides by 0.2
4=-B
times -1
-4=B
distance between 2 points x and y is |x-y|
so
distance between A and B is distance between -4 and -72 or
|-72-(-4)|=|-72+4|=|-68|=68
the distance is 68
Answer:
The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
Consider the provided information.
The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .
Thus, n = 12,
σ = 5000
degrees of freedom = n-1 = 12-1 = 11
![H_0: \mu = 33700\ and\ H_a: \mu \neq 33700](https://tex.z-dn.net/?f=H_0%3A%20%5Cmu%20%3D%2033700%5C%20and%5C%20H_a%3A%20%5Cmu%20%5Cneq%2033700)
Formula to find the value of z is: ![z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Cbar%20x-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
Where
is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.
![z=\frac{36800-33700}{\frac{5000}{\sqrt{12}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B36800-33700%7D%7B%5Cfrac%7B5000%7D%7B%5Csqrt%7B12%7D%7D%7D)
![z=2.148](https://tex.z-dn.net/?f=z%3D2.148)
Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.