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lesantik [10]
4 years ago
10

What creates a bubble of hot ionized gas?

Physics
1 answer:
MAVERICK [17]4 years ago
4 0
The high-speed gas is thrown into space by a supernovae or strong stellar winds which  collects i<span>nterstellar</span><span> material, excavating a </span>bubble of hot<span>, </span>ionized gas 
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Suppose the first coil of wire illustrated in the simulation is wound around the iron core 7 times. Suppose the second coil is w
SVETLANKA909090 [29]

Answer:

Emf induced in the coli will be equal to 26 volt

Explanation:

We have given number of turns N = 13

It is given that magnetic flux changes from 2.1 Weber to 2.7 Weber in 0.3 sec

Change in flux d\Phi =2.7-2.1=0.6Weber

Change in time dt = 0.3 sec

We have to find the induced emf

Induced emf is equal to e=N\frac{d\Phi }{dt}=13\times \frac{0.6}{0.3}=26volt

So emf induced in the coil will be equal to 6 volt

5 0
3 years ago
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Could anyone help with number 9?
Alisiya [41]
The answer would be A
3 0
3 years ago
If the net force acting on a stationary object is zero, then the object will A. remain at rest. B. accelerate in the direction o
ra1l [238]

The object will remain at rest

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Here net force is zero

An object with a net force of zero acting on it will remain at rest, if initially at rest, or it will maintain a constant velocity.

F=MA

Force F=0

Than Acceleration A=0

With zero Acceleration stationary object  will remain at rest.

Hence Remain at rest is the correct answer

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6 0
2 years ago
What compound is a product of photosynthesis?
Aleksandr-060686 [28]
Glucose, they produce that when going thru photosynthesis!
7 0
3 years ago
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A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of
Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

F=ILB sin \theta

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

\theta is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

L = 5 m

\theta=90^{\circ}

Substituting into the equation, we find

F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N

6 0
3 years ago
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