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2 years ago

I need help with one through six please

Physics

1 answer:

dybincka [34]2 years ago

7 0

Answer:

1] 8500000 = 8.5 × 10⁶

2] .000072 = 7.2 × 10⁻⁵

3] 5.3 × 10⁴ = 53000

4] 2.8 × 10⁻³ = 0.0028

5] Velocity = $\frac{distance}{time}$

V = $\frac{50}{10}$

V = 5 m/s

6] Acceleration = $\frac{V1-V2}{time}$

A = $\frac{30-15}{3}$

A = $\frac{15}{3}$

A = 3 m/s²

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To solve the problem it is necessary to consider the concepts related to Potential Energy and Kinetic Energy.

Potential Energy because of a planet would be given by the equation,

$PE=\frac{GMm}{r}$

Where,

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M = Mass of Moon

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From the data given we can calculate the mass of the ocean water through the relationship of density and volume, then,

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$PE_1 = \frac{GMm}{r_1}$

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PART B) Potential energy when the ocean is at its closest point to the moon

$PE_2 = \frac{GMm}{r_2}$

$PE_2 = \frac{(6.61*10^{-11})*(7.21*10^{11})*(7.35*10^{22})}{3.776*10^8}$

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PART C) The maximum speed. This can be calculated through the conservation of energy, where,

$\Delta KE = \Delta PE$

$\frac{1}{2}mv^2 = PE_2-PE_1$

$v=\sqrt{2(PE_2-PE_1)/m}$

$v = \sqrt{\frac{2*(9.361*10^{15}-9.05*10^{15})}{7.210*10^{11}}}$

$v = 29.4m/s$

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3 years ago

Starting from rest, a wheel with constant angular acceleration turns through an angle of 25 rad in a time t. What will its angul

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Answer:

θ = 225 rad

Explanation:

given data

angle = 25 rad

to find out

angular velocity after 3t?

solution

let angular acceleration α in t

θ = ω × t + 0.5 × α × t² ........................1

here ω = 0 (initial velocity )

so put this value here

25 = 0 + 0.5 × α × t² ..........................2

α = 25 ÷ (0.5 t²)

α = 50 ÷ t² .........................3

now here we take in 3t

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for ω = 0

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now put value in eq 2

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