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2 years ago

I need help with one through six please

Physics

1 answer:

dybincka [34]2 years ago

7 0

Answer:

1] 8500000 = 8.5 × 10⁶

2] .000072 = 7.2 × 10⁻⁵

3] 5.3 × 10⁴ = 53000

4] 2.8 × 10⁻³ = 0.0028

5] Velocity = $\frac{distance}{time}$

V = $\frac{50}{10}$

V = 5 m/s

6] Acceleration = $\frac{V1-V2}{time}$

A = $\frac{30-15}{3}$

A = $\frac{15}{3}$

A = 3 m/s²

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1600 AM broadcasts radio waves with wavelengths of about 187.37 m. Convert this to miles.

nikklg [1K]

Answer:

The wavelength in miles is 0.1165 miles.

Explanation:

Given:

Wavelength of the radio wave is 187.37 m.

Now, the wavelength is given in meters.

We need to convert the wavelength from meters to miles.

In order to convert meters to miles, we have to use their conversion factor.

We know that,

1 meter = $\frac{1}{1609}\ miles$

Therefore, the conversion factor is given as:

$CF=\frac{1}{1609}\ miles\ per\ meter$

So, the wavelength in miles is given as:

$Wavelength=\textrm{Wavelength in meters}\times CF\\\\Wavelength=187.37\ m\times \frac{\frac{1}{1609}\ miles}{1\ m}\\\\Wavelength=\frac{187.37}{1609}\ miles\\\\Wavelength=0.1165\ miles$

Hence, the wavelength in miles is 0.1165 miles.

7 0

3 years ago

A Jeep Rubicon has a mass of 2,630 kg. With a momentum of 55,200 kg m/s. What was the speed, in m/s, of the vehicle?

Annette [7]

Answer:

The speed of the vehicle was 21 m/s

Explanation:

Momentum can be defined as mass in motion

Momentum depends on the variables mass and velocity

The momentum of an object is equal to the mass of the object times the

velocity of the object

The given is:

→ A Jeep Rubicon has a mass of 2,630 kg

→ With a momentum of 55,200 kg m/s

We need to find the speed of the vehicle

→ The momentum = mass × speed

Substitute the values above in the rule

→ 55,200 = 2,630 × speed

Divide both sides by 2,630

→ speed = 20.99 ≅ 21 m/s

The speed of the vehicle was 21 m/s

4 0

3 years ago

Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of

Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

$A=2\times10^{-6}m^2$

* The young modulus of the steel is,

$Y=2.1\times10^{11}\text{ Pa}$

Solution:

The young modulus of the steel in terms of the force and extension is,

$Y=\frac{F\times l}{A\times dl}$

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

$\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}$

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0

11 months ago

At what angle torque is half of the max

denis-greek [22]

At what angle torque is half of max

8 0

2 years ago

In a jump spike, a volleyball player slams the ball from overhead and toward the opposite floor. controlling the angle of the sp

8090 [49]

V ( initial ) = 20 m/s
h = 2.30 m
h = v y * t + g t ² / 2
d = v x * t
1 ) At α = 18°:
v y = 20 * sin 18° = 6.18 m/s
v x = 20 * cos 18° = 19.02 m/ s
2.30 = 6.18 t + 4.9 t²
4.9 t² + 6.18 t - 2.30 = 0
After solving the quadratic equation ( a = 4.9, b = 6.18, c = - 2.3 ):
t 1/2 = (- 6.18 +/- √( 6.18² - 4 * 4.9 * (-2.3)) ) / ( 2 * 4.9 )
t = 0.3 s
d 1 = 19.02 m/s * 0.3 s = 5.706 m
2 ) At α = 8°:
v y = 20* sin 8° = 2.78 m/s
v x = 20* cos 8° = 19.81 m/s
2.3 = 2.78 t + 4.9 t²
4.9 t² + 2.78 t - 2.3 = 0
t = 0.46 s
d 2 = 19.81 * 0.46 = 9.113 m
The distance is:
d 2 - d 1 = 9.113 m - 5.706 m = 3.407 m

GOOD LUCK AND HOPE IT HELPS U

6 0

3 years ago