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Pavel [41]
3 years ago
15

PLEASE HELP ASAP WILL GIVE BRAINLIEST ​

Physics
2 answers:
stealth61 [152]3 years ago
4 0

Explanation

(m) is measured in kilograms (kg)

<h2>(F) is measured in newtons (N)</h2>

<h3>acceleration (a) is measured in metres per second squared (m/s²)</h3>
Nikolay [14]3 years ago
4 0

Q1) <em>~</em><em>mass (m) is measured in kilograms (kg) </em>

Q2)<em>~</em><em>acceleration (a) is measured in metres per second squared (m/s²)</em>

Q3)<em>~</em><em>force (F) is measured in newtons (N)</em>

Hope this helped you- have a good day bro cya)

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20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu
Anastasy [175]

Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

7 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
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v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is supported by an upward force o
Rainbow [258]

Answer:

5..No work is being done.

Explanation:

Hello!

Remember that the concept of work is defined as the force required to move a certain body distance, it is calculated as the product of force by distance.

therefore, the work required to raise the box is 150J.

However, the work required to keep the box lifted without moving is zero since although the box has a force due to the weight it does not move.

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3 years ago
Why is gravitational acceleration almost always a factor in determining pressure?
Scorpion4ik [409]

Explanation:

Newton's law of universal gravitation states that every object attracts every other object with a force. For any two objects, this force is directly proportional to the mass of each object. The greater the masses, the greater the force of attraction between them. Newton also deduced that this force decreases as the square of the distance between the centers of the objects increases. The farther away the objects are from each other, the less the force of attraction between them.

7 0
3 years ago
The atomic number of an element is found by?
azamat

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6 0
3 years ago
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