In ΔEFG, the measure of ∠G=90°, EF = 95 feet, and FG = 26 feet. Find the measure of ∠F to the nearest degree.
2 answers:
Answer:
74.4°
Step-by-step explanation:
Given
- ∠G=90° => ΔEFG is a right triangle
- EF = 95 feet
- FG = 26 feet
Use sine law to find ∠F
As we know:
Sin(GEF)/ GF = Sin(EGF)/EF
<=> Sin(GEF) / 26 = Sin(90)/95
<=>Sin(GEF) / 26 = 1/95
<=> Sin(GEF) = 26/95
<=> ∠GEF ≈ 15.8°
=> ∠F = 180° - ∠G - ∠GEF
∠F = 180° - 90° - 15.8° = 74.4°
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Answer:
(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.
Step-by-step explanation:
Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.
If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
- np ≥ 10
- n(1 - p) ≥ 10
The three populations has the following proportions:
p₁ = 0.10
p₂ = 0.30
p₃ = 0.50
(1)
Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2)
Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3)
Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.