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2 years ago

6

Which BEST describes the construction of a triangle if given one side length of 10 cm and one right angle?

1 answer:

Colt1911 [192]2 years ago

4 0

Statements that best describe the triangle are the following:
1. It is a right triangle, therefore one angle is equivalent to 90°.
2. We can solve for the measurement of the other leg using the Pythagorean theorem c²=a²+b².
3. We can use SOH CAH TOA theorem in solving the other unknowns.

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How to simplify <br> -6k +7k<br> 12r -8 -12<br> n -10 +9n -3<br> -4x-10x<br> -r -10r

Semmy [17]

Answer:

Solve by adding or subtracting like terms. (Ex. 2k + 4k = 6k; 9 + 7 = 16)

- 6k + 7k = 1k = k

(7 - 6 = 1)

12r - 8 - 12 = 12r - 20

(8 + 12 = 20 but sign is negative) 12r will stay the same because there are no terms with a letter r.

n - 10 + 9n - 3 = 9n + n - 10 - 3 = 10n - 10 - 3 = 10n - 13

(n = 1 so 9 + 1 = 10; 10 + 3 = 13 but negative sign)

- 4x - 10x = 14x

(10 + 4 = 14)

- r - 10r = 11r

(r = 1 so 10 + 1 = 11)

6 0

3 years ago

Hey ill give brainlist

TEA [102]

Answer:

$2.\:\frac{41}{9}$

Step-by-step explanation:

Recall that $\frac{x}{9}=\lfloor \frac{x}{9} \rfloor + 0.\overline{[x\:\mod9]}$ .

Therefore, $4.\bar{5}=\frac{4\cdot 9 + 5}{9}=\fbox{$2)\:\frac{41}{9}$}$ .

5 0

2 years ago

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5. A yacht is cruising at 20 knots at bearing of 185° when a 15 knot wind starts to blow at a bearing of 290°. Find the directio

kicyunya [14]

Answer:

<em>Direction of the boat is 43.05° and the speed is 21.66 knot</em>

<em></em>

Step-by-step explanation:

yacht speed = 20 knots

yacht bearing = 185° = 85° below the negative horizontal x-axis

wind speed = 15 knots

wind bearing = 290° = 20° above the negative horizontal x-axis

we find the x and y components of the boat velocities

for yacht,

x component = -20 cos 85° = -1.74 knots

y component = -20 sin 85° = -19.92 knots

for the wind,

x component = -15 cos 20° = -14.09 knots

y component = 15 sin 20° = 5.13 knots

total x component Vx = -1.74 + (-14.09) = -15.83 knots

total y component Vy = -19.92 + 5.13 = -14.79 knots

Resultant speed of the boat = $\sqrt{Vx^{2} + Vy^{2} }$

==> $\sqrt{15.83^{2} + 14.79^{2} }$ = <em>21.66 knot</em>

<em></em>

direction of boat = $tan^{-1} \frac{Vy}{Vx}$

==> $tan^{-1} \frac{14.79}{15.83}$ = <em>43.05°</em>

3 0

3 years ago

Identify the equation in standard form of the line that passes through the point (6,−8) and has the slope of −2 .

Arturiano [62]

Answer:

y = -2x + 4

Step-by-step explanation:

y = -2x + b

-8 = -2(6) + b

-8 = -12 + b

4 = b

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2 years ago

Which of the following is a regular quadrilateral

irga5000 [103]

Answer:

(B) square

Step-by-step explanation:

Square (regular quadrilateral): all four sides are of equal length (equilateral), and all four angles are right angles.

8 0

2 years ago

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