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3 years ago

13

An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir

cle that could fit in the square, as a shown below Show work please

1 answer:

Serhud [2]3 years ago

4 0

Answer:

The artist used $8.6\ in$ more of silver wire

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

we know that

The Perimeter of the square is equal to

$P=4a$

where

a is the length side of the square

$P=40\ in$

so

$40=4a$

$a=10\ in$

so

Each side of the square has a length of 10 in

step 2

Find the circumference of the circle

The diameter of the circle is equal to the length of the side of the square

The circumference is equal to

$C=\pi D$

we have

$D=10\ in$

substitute

$C=(3.14)(10)=31.4\ in$

step 3

Find the difference

$40\ in-31.4\ in=8.6\ in$

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Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semest

strojnjashka [21]

Answer:0.9991

Step-by-step explanation:

The Poisson distribution probability formula is given by :-

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$ , where \lambda is the mean of the distribution and x is the number of success

Given : $\lambda=7$

The probability that more than 1 student will have his automobile stolen during the current semester is given by :-

$P(x\geq1)=1-P(x=0)=1-(\dfrac{e^{-7}7^0}{0!})\\\\=1-e^{-7}=0.99908811\approx0.9991$

Hence, the probability that more than 1 student will have his automobile stolen during the current semester =0.9991

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3 years ago

. Explain why projectile motion, such as kicking a ball off the top of building, has a curved path. Identify the two forces invo

deff fn [24]

The initial kick is the first force applied to the ball. It sends the ball up into the air (at some angle). If gravity wasn't present, then the ball would go upward forever in a straight line. However, gravity is the second force pulling down on the ball. This explains why the ball hits some peak point or highest point before it is pulled to the ground. Overall, the path the ball takes is a parabolic arch.

In short, the two forces are the initial kick and gravity.

side note: technically air resistance (aka air friction or drag) is a force being applied since the air pushes against the ball to slow it down, but often air resistance is really complicated and beyond the scope of many math courses. So your teacher may want you to ignore air resistance.

Another note: the initial kick is a one time force that only happens at the beginning. Once the ball is in the air, that force isn't applied anymore. In contrast, the force of gravity is always present and always pulling down. It's probably incredibly obvious, but it's worth pointing out this difference.

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3 years ago

Which function represents the equation of the line?

yanalaym [24]

\left[x \right] = \left[ 3\right][x]=[3] totally answer

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3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

Solve the system of equations.<br> y=7x<br> y=2x + 20<br><br> x=?<br> y=?

alekssr [168]

X=4, y=28. 7x=2x+20, so subtract 2x from both sides and you’ll get 5x=20. Divide both sides by 5 and you’ll get x=4. Substitute this into the other equations and they will both equal 28.

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2 years ago