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-BARSIC- [3]
4 years ago
7

Misha increased her test score from 60% to 80%. What was the approximate percent increase of Misha's test score?

Mathematics
1 answer:
Doss [256]4 years ago
3 0
The approximate percent increase of Misha's test score is 33%. The correct answer between all the choices given is the second choice. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
You might be interested in
How do you describe the end behavior of a graph?
timofeeve [1]

Answer:

The end behavior of a function [f] describes the behavior of the graph of the function [f] at the ends of the x-axis.

Step-by-step explanation:

I've done this last year and this is what I can come up with

7 0
1 year ago
State all integer values of x in the interval (2,8) that satisfy the following inequality:
lidiya [134]

Answer:

3,4,5,6 and 7

Step-by-step explanation:

Given

5x + 4 \ge 19

Required

State the values of x within 2 and 8

5x + 4 \ge 19

Collect Like Terms

5x \ge 19 - 4

5x \ge 15

Divide both sides by 5

\frac{5x}{5} \ge \frac{15}{5}

x \ge 3

(2,8) is an open interval which means that 2 and 8 are not inclusive of the values of x.

So:

The values of x \ge 3 are: 3,4,5,6 and 7

3 0
3 years ago
Find the coordinates of the transformed image when the pre-image is reflected over the line x=2
zepelin [54]
A’= (10,1)
B’= (8,1)
C’= (9,5)
D’= (7,5)

hope this helps!
8 0
3 years ago
If you wanted to make the graph of y = 8x - 10 less steep, as well as shift the
azamat

Answer:

4x-15=y

Step-by-step explanation:

The higher the rise over the run the more steep your slope will be thus 4x is less steep than 8x because it does not rise as much.

The y intercept shifted downward means anything (-10>b) can be plausible for b.

3 0
3 years ago
An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1

surface area of the box=area of the base+perimeter of base*height

area of the base=b²
perimeter of the base=4*b

surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2

substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b

the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
4 0
3 years ago
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