Answer:
Option A.
Step-by-step explanation:
We need to find a table for which the y-value will be the greatest for very large values of x.
From the given table it is clear that the largest value of x in all tables is 5.
In table A, y=64 at x=5.
In table B, y=32 at x=5.
In table C, y=40 at x=5.
In table D, y=13 at x=5.
It is clear that 64 is the greatest value among 64, 32, 40 and 13.
It means table in option A represents the function for which the y-value will be the greatest for very large values of x.
Therefore, the correct option is A.
So a point is (-3,-5) and the vertex is (-4,-3)
This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.
The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)
I will choice -3. This gives -2(-3+4)^2-3
f(-3)=-2(1)^2-3
f(-3)=-2-3
f(-3)=-5
Let the Width(W) =X feet
then Length(L) = (2X-3)feet
Area of the rectangle (A)=77 square feet
A = L× W
L×W=A
(2X-3) × X = 77
2X²- 3X =77
2X²-3X -77=0
Solving it using the factorization method
2X²-14X+11X-77=0
(2X²-14X)+(11X-77)=0
2X(X-7) + 11(X-7)=0
(2X+11)(X-7) =0
When 2X+11=0
X= -11/2
When X-7=0
X = 7
Therefore X= 7
Width = X feet
= 7feet
The width is 7feet
Length = (2X-3)feet
= (2×7) -3)feet
=(14-3)feet
=11feet
185
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,2021.22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40
I give up
