T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
You want to use the addition property, so you need to ADD each term. Just change the minuses to pluses, making sure you keep the negative with the number
5x-8x-7y+y =
5x + -8x + -7y +y
Step-by-step explanation:
2πrh+2πr²=surface area
2π(3)(6)+2π(3²)
36π+18π
54π
I'm not 100% sure but I think it's 10:10 because of the Spoons - 10:30.
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