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____ [38]
3 years ago
11

Select the correct answer.

Mathematics
1 answer:
Drupady [299]3 years ago
8 0

Answer: A

Step-by-step explanation:

because i did a quiz with the same and i got it right

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Which additional information is needed to solve this story problem? The zoo had 3 baby pandas in 2006 and gave 2 of them to othe
Likurg_2 [28]

Answer:

How may pandas were born in 2006

Step-by-step explanation:

7 0
3 years ago
Water flows down the Mississippi River at about 1.2 miles per hour
Angelina_Jolie [31]

Answer:

Continuous

Step-by-step explanation:

The rate of flow of water down the river is referred to as its speed. Thus the speed changes with respect to the distance covered. Which implies that there is a direct relationship between the distance covered (in miles) by the water flow and time taken (in hours).

The relationship between hours and miles the water traveled is continuous.

6 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
I need help plz i dont get it and im trying to get my grade up
Ymorist [56]

Answer:

648

Step-by-step explanation:

(25 - 9 + 2)^2 / 3x6

= 108 x 6

= 608

follow BODMAS and you'll get it

If you would like to venture further, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

4 0
3 years ago
Read 2 more answers
Find the angle between the given vectors to the nearest tenth of a degree. u = (8, 4), v = (9, -9)
Usimov [2.4K]

Answer:

<em>71.6 degrees </em>

Step-by-step explanation:

The formula for calculating the angle between two vectors is expressed as;

u.v = |u||v|cos theta

u.v = (8, 4).(9, -9)

u.v = 8(9)+4(-9)

u.v = 72-36

u.v = 36

|u| = √8²+4²

|u| = √64+16

|u| = √80

|v| = √9²+(-9)²

|v| = √81+81

|v| = √162

36 = √80*√162 cos theta

36 = √12960 cos theta

36 = 113.84 cos theta

cos theta = 36/113.84

cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

7 0
3 years ago
Read 2 more answers
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