Answer:
Explanation:
Both the B cell membranes and the cancer cells are composed largely of phospholipids. Explain how the polar parts of the phospholipids from one cell interact with the phospholipids from the other cell when the membranes are fused, and how the nonpolar parts of one-cell phospholipids interact with the phospholipids from the other cell.
The polar parts of the phospholipids (hydrophilic head) from one cell to the other dissolve in water when the membranes are fused, and form hydrogen bonds with water. The non-polar portions of the phospholipids (hydrophobic tail) from one cell to the next to prevent water. They build a lipid bilayer between the hydrophilic heads where the hydrophobic tails are in between.
The heads are exposed to water when this layer is formed, while the tails only communicate with other tails, not the water.
The molecular weight of glucose is approximately 180 daltons so each mol of glucose will be equal to 180g glucose. The concentration of glucose in the blood would be: 100mg/dl * 1 mol/180g= 5.55 mol/dl * 10^-4
Molar is expressed as mol per liter, so you need to change the volume into liters. The calculation would be: 5.55 mol/dl * 10^-4 * 10dl/liter= 5.55 * 10^-3 M= 5.55 millimoles
Answer:
The correct answer is - less efficient signaling.
Explanation:
Second messengers are the molecules that help in transferring the information in the form of intracellular signal that has come from external stimulus.
Second messenger molecules should be short-lived as the concentration of these molecules should be decreased fastly so the cell can be available for other stimuli mediated by the same second messenger.
With increased lifetime, signaling will be less efficient as another stimulus cannot be detected.
Thus, the correct answer is - less efficient signaling.