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Anika [276]
3 years ago
10

One similarity between a small, solid

Chemistry
1 answer:
Firdavs [7]3 years ago
7 0

Answer:

c.The same number of atoms.

Explanation:

if the same amount of solid aluminium is converted to liquid aluminium then we will have same amount of atoms.

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A double-replacement reaction takes place when aqueous k2so4 reacts with aqueous pb(no3)2. you would expect the products of this
SpyIntel [72]
A double replacement is when the reactants switch with their opposite charge. For example, AB + CD = AD + BC.

In this case the given is K2SO4 + Pb(NO3)2 = ____ + ____

The answers is PbSO4 and KNO3 would expect the products of this reaction.
8 0
3 years ago
Read 2 more answers
what if your friend joked that a cell is like his little brother's bathtub with tub toys floating in it
Natasha2012 [34]

Answer:

no

Explanation:

a cell is something that either stays inside of something or is a individual floating object and it does not compare to bigger sized materials

5 0
4 years ago
4Ga + 3S2 → 2Ga2S3
emmasim [6.3K]

Answer:

118.4 g

Explanation:

4 Ga  +  3 S₂ → 2 Ga₂S₃

According to the equation, for every 4 moles of gallium burned, 2 moles of gallium(III) sulfide.

First, convert grams of Ga₂S₃ to moles.  The molar mass is 235.641 g/mol.

(200.0 g)/(235.641 g/mol) = 0.8487 mol

Use the relationship above to convert moles of Ga₂S₃ to moles of Ga.

(0.8487 mol Ga₂S₃) × (4 mol Ga)/(2 mol Ga₂S₃) = 1.697 mol Ga

Convert moles of Ga to grams.  The molar mass is 69.723 g/mol.

(1.697 mol Ga) × (69.723 g/mol) = 118.4 g

5 0
3 years ago
1. Which statement describes the charge and location of an electron in an atom? A) An electron has a positive charge and is loca
damaskus [11]

Answer: option c an electron has a negative charge and is located outside the nucleus revolving in circular path

7 0
3 years ago
Calculate the number of moles of solute present and the number of grams
nekit [7.7K]

Answer:

The answer is: 18 moles and 1341, 72 grams of KCl

Explanation:

The molarity is defined as the moles of solute ( in this case KCl) in 1 liter of solution:

1L solution-----3 moles of KCl

6L solution-----x= (6L solutionx 3 moles of KCl)/1 L solution= <em>18 moles of KCl</em>

<em></em>

We calculate the weight of 1 mol of KCl:

Weight 1 mol KCl= Weight K + Weight Cl= 39,09 g + 35, 45 g=74, 54 g/mol

1 mol KCl----- 74, 54 g

18 mol KCl----x= (18 mol KCl x 74, 54 g)/1 mol KCl=<em>1341, 72 g</em>

6 0
4 years ago
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