Answer:
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide gas = 
V = Volume of carbon dioxide gas = 3.0 L
n = number of moles of carbon dioxide gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of carbon dioxide gas =0°C = 0+273= 273 K
Putting values in above equation, we get:
Mass of 0.13 mole carbon dioxide gas :
= 0.13 mol × 44 g/mol = 5.7 g
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.
1 cm ------------ 10 mm
5,678 cm ------- ?
5,678 x 10 / 1 => 56,78 mm
Answer:
Explanation:
When heat is supplied to a substance, the temperature of the substance increases according to:
where
Q is the amount of heat supplied
m is the mass of the substance
C is the specific heat capacity of the substance
is the initial temperature
is the final temperature
For the sample of magnesium in this problem, we have:
m = 63 g is the mass
Q = 6689 J is the hear supplied
C = 1.023 J/gC is the specific heat capacity
is the final temperature
Solving the formula for , we find the final temperature:
First of all write a balanced equation.
4Na + O2 -> 2Na2O
You are starting with a mass of sodium. You need to use sodium’s molar mass. Take this quantity times mole to mole ratio between sodium and sodium oxide to get moles of sodium oxide produced.
.141 moles of sodium oxide produced
