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damaskus [11]
3 years ago
10

(c) Polar solutes were separated by hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase. How would

retention times be affected if eluent were changed from 80 vol% to 90 vol% acetonitrile in water?
(d) Polar solutes were separated by normal-phase chromatography on bare silica using methyl '-butyl ether and 2-propanol solvent. How would retention times be affected if eluent were changed from 40 vol% to 60 vol% 2-propanol? (Hint: See la..12.l.g-2.i.:A.)
Chemistry
1 answer:
Lelu [443]3 years ago
5 0

Answer:

(c) The retention time would be higher (d) The retention time would be lower.

Explanation:

For the polar solutes which were separated using the hydrophilic interaction chromatography (HILIC) with a strongly polar bonded phase, the retention time would be higher if eluent were changed from 80 vol% to 90 vol% acetonitrile in water.

However, for the polar solutes which were separated using the normal-phase chromatography on bare silica with methyl t=butyl ether and 2-propanol solvent, the retention time would be lower if the eluent were changed from 40 vol% to 60 vol% 2-propanol.

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miss Akunina [59]

Answer:

CaCl2, Li2S, AlCl3, AlCl3, K2S

Explanation:

When figuring out which is a better conductor of electricity you want to look at which has the largest yield of dissociated ions.

6 0
3 years ago
5. calculate the percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o
ki77a [65]

The percentage of water of crystallization in blue vitriol is 36.07%.

M(H₂O) = 2Ar(H) + Ar(O) x g/mol

M(H₂O) = 2 + 16 x g/mol

M(H₂O) = 18 g/mol; molar mass of water

M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol

M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol

M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate

The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%

The percentage of water: 90 g/mol / 249.5 g/mol x 100%

The percentage of water = 36.07%

More about blue vitriol: brainly.com/question/8895853

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5 0
1 year ago
Read 2 more answers
Devise a way to separate a mixture of sand, salt, and iron filings. Write the procedure using a step-by-step method and explain
aev [14]
1. Iron fillings are magnetic, so use a magnet to pull the iron fillings out of the mix.
2. Then you can put the salt and sand mixture into water, since salt is soluble, and the salt will dissolve, leaving you with sand.
3 0
3 years ago
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of w
Margarita [4]

Answer:

$10.97 \ g/cm^3$

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level $\text{in the graduated cylinder}$ = 25 mL

Final water level $\text{in the graduated cylinder}$ = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = 10.5 \ cm^3

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = 10.5 \ cm^3

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

$\rho =\frac{\text{mass}}{\text{volume}}$

$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$

  = $10.97 \ g/cm^3$

3 0
3 years ago
The chemical equation shows how ammonia reacts with sulfuric acid to produce ammonium sulfate. 2NH3(aq) + H2SO4(aq) (NH4)2SO4(aq
Gemiola [76]

D. 7,930 g ................................ believe me

5 0
3 years ago
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