Question

Write the equilibrium constant expression for this reaction: CH3OH (aq)+Cl-(aq)-> CH3Cl(aq)+OH-(aq)

Answer 1

Answer: $K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}$

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. Pure solids are assumed to have a concentration of 1.

The given balanced equilibrium reaction is:

 $CH_3OH(aq)+Cl^-(aq)\rightleftharpoons CH_3Cl(aq)+OH^-(aq)$

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}$

Thus the equilibrium constant expression for this reaction is $K_c=\frac{[CH_3Cl]\times [OH^-]}{[CH_3OH]\times [Cl^-]}$