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3 years ago

What happens to the air as it gets farther from the heat source?

Chemistry

1 answer:

Effectus [21]3 years ago

6 0

Answer:

molecules heat and move faster, they are moving apart. So air, like most other substances, expands when heated and contracts when cooled.

Explanation:

Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward.

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The number of moles in 2.93 g of Li2O in corrext sig figs

jekas [21]

Answer:

0.1 mol

Explanation:

Number of mole= mass/molar mass

lithium have a mass number of 7 and oxygen have a mass number of 16.

so, (7x2) + 16

= 30

therefore, number of moles = 2.93/30

= 0.10

4 0

3 years ago

Read 2 more answers

A student performs an experiment to find the percentage of water in a hydrate. He determines that the hydrate contains 22% water

Stels [109]

Answer:

A feasible error could have been the removal of the sample before all water evaporated.

Explanation:

In order to determine the percentage of water in an hydrate, an experiment that could be performed is the heating of the sample until the mass does not change. If the student heated the sample an insufficient amount of time, water will be present in the sample, thus reducing the percentage reported.

4 0

3 years ago

5. What are Opioids?

Alex_Xolod [135]

The answer to your question is the first one!

6 0

3 years ago

Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will

Alla [95]

Answer:

Only $Fe^{3+}+Mg$ gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential ( $E^{0}$ ) of the reaction is positive. Because it leads to negative standard gibbs free energy change ( $\Delta G^{0}$ ), which is a thermodynamic condition for spontaneity of a reaction.

$E^{0}=E^{0}(reduction)-E^{0}(oxidation)$

Where $E^{0}(reduction)$ and $E^{0}(oxidation)$ represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation: $Mg-2e^{-}\rightarrow Mg^{2+}$ ; $E_{Mg^{2+}\mid Mg}^{0}=-2.38V$

Reduction: $Fe^{3+}+3e^{-}\rightarrow Fe$ ; $E_{Fe^{3+}\mid Fe}^{0}=-0.04V$

So, $E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V$

Hence this pair will give spontaneous reaction.

(2) Similarly as above, $E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V$

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, $E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V$

Hence this pair will give non-spontaneous reaction.

(4) Similarly as above, $E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V$

Hence this pair will give non-spontaneous reaction.

6 0

3 years ago

How many grams of water are produced from the decomposition of 63 grams of lithium hydroxide

Ymorist [56]

Answer:

18.65004 grams H2O

Explanation:

First, we need to write down the balanced chemical equation for the decomposition reaction:

2LiOH -> H2O + Li2O

Since we have grams of LiOH and we need to know the grams of water, we need to convert to moles since we can only compare moles to moles.

The amu of LiOH is 23.947.

The given grams of LiOH is 63.. To convert to moles, we will divide 63 by 23.947..

This gives us 2.6310 moles LiOH..

To convert to moles of H2O (and later grams of H2O), we will use the mole fractions from the balanced equation...

When we look at the balanced equation we can see that 2 moles of LIOH can produce 1 mol of Water, so:

2.6310 moles $* \frac{1 molH_{2}O}{2 mol LiOH}$ = 1.3155 moles H2O

Now we will convert from moles to grams (we must multiply by the amu)

1.3155 moles H2O = 18.65 grams H2O

3 0

3 years ago