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Gekata [30.6K]
3 years ago
9

A multiple-choice test consists of 10 questions. Each question has answer choices of a ,b c, d ,e , and , and only one of the ch

oices is correct. If a student randomly guesses on each question, what is the probability that he gets at least 2 of them correct?
Mathematics
1 answer:
aalyn [17]3 years ago
4 0
Its easier to find the complement of that instead
so you find the probability of 1 and 0
The .2 in the answer is the probability of each question 1/5
  (10 C 0) x .2^0 (1-.2)^10-0=.1074
 (10 C 1) x .2^1 (1-.2)^10-1=.2684
.2684+.1074=.3758 and that's the complement
so 1 - .3758= .6242
I too have a stats exam on this tomorrow lol
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3^4 × h^5 × g^2 / 3^2 × h^8<br><br> Could you show me the steps so I can understand easier?
hoa [83]

Answer:

\dfrac{3^{2} \times g^{2}}{h^{3} }

Step-by-step explanation:

We have to simplify the following mathematical expression.

The expression is \dfrac{3^{4} \times h^{5} \times g^{2}}{3^{2} \times h^{8}   }

Now, \dfrac{3^{4} \times h^{5} \times g^{2}}{3^{2} \times h^{8}   }

= 3^{(4 - 2)} \times h^{(5 - 8)} \times g^{2}

{Since, all the terms are in product form, so, we can treat them separately}

{We know the formula of exponent \dfrac{x^{a} }{x^{b} }  = x^{(a - b)}}

= 3^{2} \times h^{- 3} \times g^{2}

= \dfrac{3^{2} \times g^{2}}{h^{3} } (Answer)

{Since, we know, x^{- a} = \dfrac{1}{x^{a}}}

7 0
2 years ago
A golfer shot 2 rounds of -4 each and then shot2 rounds of 2 each. What was the golfers composite score?
irakobra [83]

Answer:

Step-by-step explanation:

all answers in here just scroll

Download pdf
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> pdf </span>
3 0
2 years ago
Using the graph above, create a system of inequalities that only contains points B and C in the overlapping shaded regions. Expl
k0ka [10]

1. The system of inequality is

y < 1.5x - 3

y < -2x/3 + 4



2. A is (2,-3)

E is (3,1)

-3 < 1.5(2) - 4

-3 < -1

1 < -2(3)/3 + 4

1 < 2



3. You can graph the inequality and see which schools inside the zone. Schools C and B are the schools he is allowed to attend.



hope it helps

8 0
3 years ago
Anyone wanna attempt to help me
ArbitrLikvidat [17]

Answer:

t=57, u=31, v=92

Step-by-step explanation:

So we know that 180= 5x+2+2x+9+8x+4 which simplifies to 180 = 15x+15. Subtract 15 from both sides to get 165=15x and then divide by 15 to get 11=x. NOw we can plug this into the three angles as x so t = 5*11+2, t=55+2, t=57, then u = 2*11+9, u=22+9, u=31, and lastly v=8*11+4, v= 88+4, and v=92

7 0
2 years ago
Two pumps connected in parallel fail indepen- dently of each other on any given day. The proba- bility that only the older pump
lions [1.4K]

Answer: 0.145

Step-by-step explanation:

Since,

the Probability of the older pump failing P(fail older) = 0.10

The probability of the newer pump failing P(fail newer) = 0.05

Therefore,

The Probability of the older pump not failing P(not fail older) = 1 - 0.1

P(not fail older) = 0.9

Also,

The probability of the newer pump not failing P(not fail newer) = 1 - 0.05 = 0.95

The probability of the pumping system failing = P(not fail older)* P(not fail newer) = 0.9*0.95

P(not fail system)= 0.855

Therefore,

The probability that the pumping system will fail = 1 - P(not fail system) = 1 - 0.855 = 0.145

The probability that the pumping system will fail one day is 0.145

3 0
3 years ago
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