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WARRIOR [948]
4 years ago
7

1 point

Mathematics
1 answer:
Aleksandr [31]4 years ago
5 0

Answer:

48 different meals are being offered

Step-by-step explanation:

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

One salad, from a set of 2.

One sandwich, from a set of 4.

One side, from a set of 6.

So

T = C_{2,1}*C_{4,1}*C_{6,1} = \frac{2!}{1!(2-1)!}*\frac{4!}{1!(4-1)!}*\frac{6!}{1!(6-1)!} = 48

48 different meals are being offered

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Look at the photo<br> answers are<br> radius <br> diameter<br> center<br> circumference
Dafna1 [17]

Answer:

Diamater= D

Radius= R

Center= C

Circumference= A

Hope it Helps? :)

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3 years ago
The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains poi
Zolol [24]

Answer:

The equation of the line y= 5x+1. Line that is parallel to the function given should have the same slope as the equation which is 5. We use the point-slope form in order to find the second equation that contains the point (4,5).

y - 5 = 5(x-4)

y = 5x - 20 +5

y≈ 5x -15

4 0
3 years ago
Read 2 more answers
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algol13
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3 years ago
4x find the degree with steps​
Alex787 [66]

9514 1404 393

Answer:

  1

Step-by-step explanation:

The term has 1 variable, which has no exponent shown. When the exponent is not shown, it is understood to be 1. The degree of the term is the exponent of this single variable, so the degree is 1.

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<em>Additional comment</em>

If the term is a product of more than one variable, the degree is the sum of their exponents.

3 0
3 years ago
For each of the following scenarios state whether H0 should be rejected or not. State any assumptions that you make beyond the i
scoundrel [369]

Answer:

a)H_0 :\mu = 4\\ H_1 : \mu \neq 4 , n = 15 , X=3.4 , S=1.5 , α = .05

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{3.4-4}{\frac{1.5}{\sqrt{15}}}

t =-1.549

p- value = 0.607(using calculator)

α = .05

p- value > α

So, we failed to reject null hypothesis

b)H_0 :\mu = 21\\ H_1 : \mu < 21 , n =75 , X=20.12 , S=2.1 , α = .10

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{20.12-21}{\frac{2.1}{\sqrt{75}}}

t =-3.6290

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α = .1

p- value< α

So, we reject null hypothesis

(c) H_0 :\mu = 10\\ H_1 : \mu \neq 10, n = 36, p-value = 0.061.

Assume α = .05

p-value = 0.061.

p- value > α

So, we failed to reject null hypothesis

7 0
3 years ago
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