we can always find the x-intercept by simply settting y = 0, and solving for "x".
and we can always find the y-intercept by simply setting x = 0 and solving for "y".
![\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (0,4)~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20x-4y%3D-16%5Cimplies%20%5Cstackrel%7Bx%3D0%7D%7B0-4y%3D-16%7D%5Cimplies%20y%3D%5Ccfrac%7B-16%7D%7B-4%7D%5Cimplies%20y%3D4%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%280%2C4%29~%5Chfill%20)
Answer:
The last one
Step-by-step explanation:
FInd a common demominator which is 20 and multiply both so it turns into 4 19/20
Answer:
m=3/4
Step-by-step explanation:
first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)
we have the equation 4x+3y=9
subtract 4x from both sides
3y=-4x+9
divide by 3
y=-4/3x+3
perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1
so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1
(m is the slope value)
-4/3m=-1
multiply by -3/4
m=3/4
therefore the slope of the perpendicular line is 3/4
hope this helps!! :)
Average of 2 numbers is 40
so total = 2 x 40 = 80
300 - 80 = 220
average of remaining 10 numbers = 220/10 = 22
answer
B) 22
She has 3 children. One children is 17, the other is 19 and the other one is 23
