All categories

2 years ago

The slope between (-3,5) and (6, -4)

Mathematics

2 answers:

gregori [183]2 years ago

4 0

Answer:

-1

Step-by-step explanation:

Andreas93 [3]2 years ago

3 0

Answer:

This a perpendicular slope

Step-by-step explanation:

You might be interested in

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27 pi

Lerok [7]

Answer:

9 cm

Step-by-step explanation:

Use the cone volume formula, V = $\pi$ r² $\frac{h}{3}$

Plug in the volume and radius, and solve for h, the height:

V = $\pi$ r² $\frac{h}{3}$

27 $\pi$ = $\pi$ (3²) $\frac{h}{3}$

27 $\pi \\$ = 9 $\pi$ $\frac{h}{3}$

3 = $\frac{h}{3}$

9 = h

So, the height of the cone is 9 cm

7 0

3 years ago

Find the product. Type your answer in the provided space. Do not use spaces in your answer. To demonstrate an exponent, use the

mel-nik [20]

Answer:

15x²6y² .................

3 0

2 years ago

Help please due now

umka21 [38]

Answer:

hii here is your answer

6 0

2 years ago

Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of

Svetach [21]

What we know:
Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 7 liters of natural oil for every 5 liters of synthetic oil.

What we need to find:
If 355 liters of synthetic oil are used, how many liters of petrolyn oil will be made?

Set up a proportion to find how much natural oil is used.
7L natural oil/5L synthetic oil = x/355 synthetic oil where x=natural oil
7/5=x/355
(5)(x)=(7)(355) cross multiplied
5x=2485 simplified
5/5x=2485/5 multiplicative inverse
x=497L

Now, add both synthetic oil and natural oil to find amount of petrolyn oil.

355 L synthetic oil + 497 L natural oil= 852 L of petrolyn oil

5 0

3 years ago

Which answer is equivalent to<br> ??? Help please

grigory [225]

Answer:

$\large\boxed{\dfrac{36}{25}}$

Step-by-step explanation:

$\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}$

7 0

3 years ago