B = 2 + 2H
A = 20 ft^2
H = H
Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20
Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.
Since b = 2h+2
b= 2(2.7) + 2
b= 5.4 + 2
b=7.4
I don't know where you got 4 and 10, but what I got is different.
Answer:
The line the foci will be graphed is?
y=0
The foci are located at about ?
(4.58, 0) and (-4.58, 0)
What type of lines will the directrices be?
Both vertical
The directrices are located at about?
x= 5.46 and x= -5.46
Step-by-step explanation:
200-(25•2)=150
150-(22•3)=84
84-25=59
Andrew has $59 left
You would multiply by the reciprocal (flip the fraction)
5/3 * 24 = 40
b = 40
