Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
12-4=8 which means 12-8=4 which means now you have the difference of 4 and 8+4=12 which means now you have the sum of 12
Answer:
x=6 y=-3
Step-by-step explanation:
<span>x=<span><span><span>−5</span>2</span>+<span><span><span><span>12</span><span>√13</span></span><span> or </span></span>x</span></span></span>=<span><span><span>−5</span>2</span>+<span><span><span>−1</span>2</span><span>√<span>13</span></span></span></span>
