A) Possible outcomes are ...
(1, 3), (1, 4), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)
for a total of 7 out of 36 outcomes that match your requirements.
p(3 < sum ≤ 5) = 7/36
B) Possible outcomes are ...
(6, 1), (6, 3), (6, 5), (1, 6), (3, 6), (5, 6)
for a total of 6 out of 36 outcomes that match your requirements.
p(6 and odd) = 6/36 = 1/6
1. This is one confusing question... But here is what I did
x = 2y + 1
y =

+ 2x
So plug in Y to solve for X
x = 2 (

+ 2x) + 1
x =
- 
Not sure if that's completely correct, but I'm positive I didn't make any mistakes...
5. You have to find the multiples of 60 so...
1 60
2 30
3 20
4 15
<span>5 12
<---
7 = 12 - 5</span>
The last one correctly uses the distributive property
Answer:
Step-by-step explanation:
eq of circle is (x-h)²+(y-k)²=r²
where (h,k) is center of circle and r is the radius.
given eq. of circle is (x+10)²+(y-4)²=100
or {x-(-10)}²+(y-4)²=10²
center is (-10,4)
and radius =10 units
Answer: F=140
Step-by-step explanation:
720=(x-60)+(x-40)+(x-20)+130+120+110
720-130-120-110=3x-120
360=3x-120
360+120=3x
480=3x
480/3=x
160=x
F=160-20
Next problem
102+31+x=180
133+x=180
x=180-133
x=47