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alisha [4.7K]
3 years ago
8

3. If a triangle has a height of 12 inches and a base of 5 inches, what's its area?

Mathematics
2 answers:
Mrac [35]3 years ago
4 0

Answer:I believe it's 30.

Step-by-step explanation: 12*5=60 For a triangle you divide by two when you find the product. So

60/2=30 .

katovenus [111]3 years ago
3 0

Answer:

30

Step-by-step explanation:

the formula is 1/2 base times the height

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ZA and ZB are complementary angles. If m_A= (7x + 28)° and m
snow_lady [41]

Answer:

mA=56 degrees

Step-by-step explanation:

Complementary angles adds up to 90 degrees. This imply that

(7x+28)+(8x+2)=90

From this equation, we can find x:

15x+30=90\\15x=90-30\\15x=60\\x=\frac{60}{15}\\x= 4

Now, we can substitute the value for x into the angle mA:

mA=(7*4+28)\\mA=(28+28)\\mA=56

7 0
3 years ago
How do if-then statements describe mathematical relationships?
Lelechka [254]

Answer:

Math relationships

Step-by-step explanation:

A mathematical relation is, a relationship between sets of numbers or sets of elements. Often you can see relationships between variables by simply examining a mathematical equation. Many physical relationships in electrostatics, electrodynamics, thermodynamics, etc. are expressed by mathematical equations. hope this helps you :)

6 0
3 years ago
(y=x-4<br> (y=-2x+5 ................................................................
harkovskaia [24]
I don’t know the answer
4 0
3 years ago
Help with this question, please!
uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0
3 years ago
HELP PLEASE!
wel

Answers:

\text{Perimeter} = 14\sqrt{5}\\\\\text{Area} = 50\\\\

=======================================================

Work Shown:

L = 2\sqrt{5} = \text{length}

W = 5\sqrt{5} = \text{width}

P = perimeter

P = 2*(L+W)\\\\P = 2*(2\sqrt{5}+5\sqrt{5})\\\\P = 2*(7\sqrt{5})\\\\P = 14\sqrt{5}\\\\

-------------

A = area

A = L*W\\\\A = (2\sqrt{5})*(5\sqrt{5})\\\\A = (2*5)(\sqrt{5}*\sqrt{5})\\\\A = 10\sqrt{5*5}\\\\A = 10\sqrt{25}\\\\A = 10*5\\\\A = 50\\\\

3 0
3 years ago
Read 2 more answers
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